Answer:
X = Water (H2O) ; Y = Hydrogen ; Z = Oxygen
Explanation:
2(H2O) -------> 2H2 + O2
Answer:
0.7g of HCl
Explanation:
First, let us write a balanced equation for the reaction between HCl and Al(OH)3.
This is illustrated below:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
Next, let us obtain the masses of Al(OH)3 and HCl that reacted together according to the equation. This can be achieved as shown below:
Molar Mass of Al(OH)3 = 27 + 3(16+1)
= 27 + 3(17) = 27 + 51 = 78g/mol.
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g
Now we can obtain the mass of HCl that would react with 0.5g of Al(OH)3. This can be achieved as follow:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
From the equation above,
78g of Al(OH)3 reacted with 109.5g of HCl.
Therefore, 0.5g of Al(OH)3 will react with = (0.5 x 109.5)/78 = 0.7g of HCl
Deposition. Particles settle to the bottom of still water after being eroded.
Answer:
-75 cm^3/min
Explanation:
Given from Boyle's law;
PV=C
From product rule;
VdP/dt + PdV/dt = dC/dt
but dC/dt = 0, V= 500 cm^3, P= 200kPa, dP= 30kPa/min
PdV/dt = dC/dt - VdP/dt
dV/dt = dC/dt - VdP/dt/ P
substituting values;
dV/dt = 0 - (500 * 30)/200
dV/dt = -75 cm^3/min
