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tigry1 [53]
3 years ago
5

The graph below compares the total amounts of greenhouse gas emissions expected for future mid-size cars, including emissions th

at
occur when moving fuels from their original source to fueling stations where people can buy the fuels for their cars. Amounts are shown in
grams of CO2 (or equivalent greenhouse gas) per mile driven by the mid-size car.

Which vehicles are the best choices for environmentally friendly cars?
A. Fuel cell Electric and battery electric
B. Hybrid electric and plug-in hybrid electric
C. Conventional internal combustion and hybrid electric
D. Conventional internal combustion and battery electric

Chemistry
2 answers:
vladimir2022 [97]3 years ago
7 0

Answer:

fuel cell electric and battery electric

Explanation:

vichka [17]3 years ago
7 0

Answer:

A. fuel cell electric and battery electric

Explanation:

They have the least amount of greenhouse gas emissions.

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When a hydrochloric acid solution is combined with a potassium hydroxide solution, an acid-base reaction occurs Write a balanced
Svetach [21]

Answer:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

Explanation:

Hydrochloric acid is an acid because it releases H⁺ in an aqueous solution.

Potassium hydroxide is a base because it releases OH⁻ in an aqueous solution.

When an acid reacts with a base they form a salt and water. This is a neutralization reaction. The neutralization reaction between hydrochloric acid and potassium hydroxide is:

HCl(aq) + KOH(aq) ⇒ KCl(aq) + H₂O(l)

7 0
4 years ago
1. Rubidium is a soft, silvery-white metal that has two common isotopes, 35Rb and Rb. The atomic mass of
xxTIMURxx [149]

Answer:

85.076572

Explanation:

= (84.911789×0.7217) + (86.909183×0.2738)

= 85.076572

8 0
3 years ago
A student dissolves of styrene in of a solvent with a density of . The student notices that the volume of the solvent does not c
raketka [301]

Answer:

0.576M and 0.655m

Explanation:

<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>

<em />

Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:

<em>Moles styrene:</em>

Molar mass C₈H₈:

8C = 12.01g/mol*8 = 96.08g/mol

8H = 1.005g/mol* 8 = 8.04g/mol

96.08g/mol + 8.04g/mol = 104.12g/mol

Moles of 15.0g of styrene are:

15.0g * (1mol / 104.12g) = 0.144 moles of styrene

<em>Liters solution:</em>

250mL * (1L / 1000mL) = 0.250L

<em>kg solvent:</em>

250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg

Molarity is:

0.144 moles / 0.250L =

<h3>0.576M</h3>

Molality is:

0.144 moles / 0.220kg =

<h3>0.655m</h3>
8 0
3 years ago
What would be the new volume if the pressure on 600 L is increased from 90.0 kPa to 150 kPa?
Liono4ka [1.6K]

Answer:

new Volume of gas=360L

Explanation:

Assume that given gas follow the ideality nature of gas

Assuming that temperature is constant;

P1 and V1 are the initial parameter of gas

and p2 and V2 are the parameter after increasing the pressure

according to boyle 's law pressure is inversly proportional to the volume at constant temperature.

P_1V_1=P_2V_2

given value of volume and gas

P1=90kPa

V1=600L

P2=150kPa

V2=?

After putting all values we get;

V2=360L

new Volume of gas=360L

7 0
3 years ago
Calculate E o , E, and ΔG for the following cell reactions (a) Mg(s) + Sn2+(aq) ⇌ Mg2+(aq) + Sn(s) where [Mg2+] = 0.025 M and [S
Rudik [331]

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

<u>Explanation:</u>

Mg(s) + Sn²⁺(aq) ⇌ Mg²⁺(aq) + Sn(s)

[Mg2+] = 0.025 M

[Sn2+] = 0.040 M

First we need the standard reduction potentials:

. . . . . . . . . . . . . . . . . E°(V)

Mg²⁺ + 2 e⁻ ⇌ Mg(s). . .−2.372

Sn²⁺ + 2 e⁻ ⇌ Sn(s) . . . −0.13

Take the more negative (or less positive in other cases) one, and write it as an oxidation:

Mg(s) ⇌ Mg²⁺ + 2 e⁻. . .+2.372 V

Combine them,

Mg(s) + Sn²⁺ ⇌ Mg²⁺ + Sn(s)

E°(cell) = +2.372 – 0.13 V = 2.24 V

To get the cell potential under the conditions given, use the Nernst Equation:

E(cell) = E°(cell) – [(0.059)/n]•logQ = 2.24 V – 0.0295 V • log [Mg²⁺]/[Sn²⁺]

Note that the solids don't appear in Q, only the concs. of the dissolved ions.

E(cell) = 2.24 V – 0.0295 V X log (0.025)/(0.040)

          = 2.24 + 0.006 V ≈ 2.246 V

The concentration ratio in Q (Sn²⁺ and Mg²⁺) is too close to 1 to shift E(cell) significantly from E°(cell) given the precision I have for the Sn reduction potential.

∆G = –nFE(cell) = –2(96.485 kJ/mol•V)(2.246 V) = –433 kJ/mol

E⁰(cell) = 2.24V

E(cell) = 2.246V

∆G = -433 KJ/mol

4 0
4 years ago
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