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ValentinkaMS [17]
3 years ago
11

A chair cost $75. The total cost of the chair was $80. What was the tax rate on the chair?

Mathematics
2 answers:
Art [367]3 years ago
6 0

Answer:

6.6%

Hope this helps!

Step-by-step explanation:

Oof I am not a fan of chairs right now!

Let's see what info we can collect:

A Chair cost= $75

Total cost + tax = $80

Our Formula:

Tax= final cost- original cost

Let's Solve!!!

Tax rate= 80-75

Tax rate= $5

Tax Percentage = 5/75 * 100

= 6.6%

Natasha_Volkova [10]3 years ago
4 0

Answer:

A chair cost $75. The total cost of the chair was $80. What was the tax rate on the chair?

A Chair cost= $75

Total cost + tax = $85

Tax= final cost- original cost

Tax rate= 85-75

Tax rate= $10

tax percentage = 10/75x100

= 13.33%

Step-by-step explanation:

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Triángulo escaleno = todos los lados son diferentes

El triángulo que se muestra aquí es isósceles porque 2 de los lados tienen la misma longitud de 7 cm.

3 0
3 years ago
Helppp and explain !!!!
GalinKa [24]

Answer:

try 4

Step-by-step explanation:

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mariarad [96]

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a. 1.8x – 10 = –4; x = 1.8 x minus 10 equals negative 4; x equals StartFraction 10 Over 2 EndFraction.

Step-by-step explanation:

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If ( 43.65 ) ( 8.79 ) / x = ( 0.4365 ) ( 87.9 ) then value of x is:
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Answer:

(d)

Step-by-step explanation:

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Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.
Allisa [31]

Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

The  check revealed that

             There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

      The sample mean is  \=  x  =  4.6 \  years

       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

4 0
2 years ago
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