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3 years ago

What do is the value of the discrimination quadratic equation 0=2x^2+x-3?

1 answer:

7 0

Hey there !

$Given \: \: equation \: \: - \: \\ \\ 2 {x}^{2} + x - 3 = 0 \\ \\ D= {b}^{2} - 4ac = {1}^{2} - 4(2)( - 3) \\ \\ D= 25$

Hope it helps you :)

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Solve 3x + 8 = 2x + 21

iren [92.7K]

<h2>Answer:</h2>

<h3>x = 13 </h3><h2>Step-by-step explanation:</h2>

<h3>3x+8=2x+21</h3><h3>solve for x3x8-2x+21</h3><h3>x8=21</h3><h3>x=21-8=13</h3><h3>solution is x=13/</h3>

<h2>HOPE IT HELPS!!!</h2>

<h2>PLZ I NEED BRAINLIEST!!</h2>

6 0

3 years ago

Read 2 more answers

Neach row, colour the one with more number of pictures

saul85 [17]

Answer

neach row, colour the one with more number of pictures

Step-by-step explanation:

neach row, colour the one with more number of pictures

5 0

3 years ago

Are the following lines parallel, perpendicular, or neither?

S_A_V [24]

Y = 7x + 12
-7y = x + 56

-7y = x + 56
-7 -7
y = ⁻¹/₇ - 8

The following lines are perpendicular.

3 0

3 years ago

Graph the equation by first finding the x- andy-intercepts.

dalvyx [7]

Answer:

x-intercept: (2,0)

y-intercept: (0,3)

Step-by-step explanation:

We are asked to graph our given equation $\frac{1}{2}x+\frac{1}{3}y=1$ .

To find x-intercept, we will substitute $y=0$ in our given equation.

$\frac{1}{2}x+\frac{1}{3}(0)=1$

$\frac{1}{2}x+0=1$

$2*\frac{1}{2}x=2*1$

$x=2$

Therefore, the x-intercept is $(2,0)$ .

To find y-intercept, we will substitute $x=0$ in our given equation.

$\frac{1}{2}(0)+\frac{1}{3}y=1$

$0+\frac{1}{3}y=1$

$3*\frac{1}{3}y=3*1$

$y=3$

Therefore, the y-intercept is $(0,3)$ .

Upon connecting these two points, we will get our required graph as shown below.

8 0

3 years ago

The school that Stefan goes to is selling tickets to a choral performance on the first day of ticket sales the school sold three

Serggg [28]

The price of 1 senior citizen ticket is $ 8

<em><u>Solution:</u></em>

Let "x" be the price of 1 senior citizen ticket

Let "y" be the price of 1 child ticket

<em><u>The school sold three senior citizen tickets and one child ticket for a total of $38</u></em>

Therefore, we frame a equation as:

three senior citizen tickets x price of 1 senior citizen ticket + one child ticket x price of 1 child ticket = 38

$3 \times x + 1 \times y = 38$

3x + y = 38 --------- eqn 1

<em><u>The school took an $52 on the second day by selling three senior citizen tickets and two child tickets</u></em>

Therefore, we frame a equation as:

three senior citizen tickets x price of 1 senior citizen ticket + two child ticket x price of 1 child ticket = 52

$3 \times x + 2 \times y = 52$

3x + 2y = 52 ---------- eqn 2

<em><u>Solve eqn 1 and eqn 2</u></em>

<em><u>Subtract eqn 1 from eqn 2</u></em>

3x + 2y - 3x - y = 52 - 38

<em><u>Substitute y = 14 in eqn 1</u></em>

3x + y = 38

3x + 14 = 38

3x = 24

Thus the price of 1 senior citizen ticket is $ 8

7 0

3 years ago