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aleksandrvk [35]

2 years ago

5

A clothing salesman want to earn $6000 in March. He receives a base salary of $4000 per mont as well as a 10% commission for all

sales in that month. How much merchandise will he have to sell to earn the amount of money he wants?

1 answer:

N76 [4]2 years ago

6 0

He would have to sell $20,000 worth of clothes to get $2,000

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Is there a picture? or something

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Simplify your answer as much as possible

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Using a graphing utility, find the exact solutions of the system. Round to the nearest hundredth and choose a solution to the sy

Margaret [11]

Answer:

Part 1) The exact solutions are

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ and $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Part 2) (1.79, 8.58)

Step-by-step explanation:

we have

$y=x^{2} +3x$ ----> equation A

$y=2x+5$ ----> equation B

we know that

When solving the system of equations by graphing, the solution of the system is the intersection points both graphs

<em>Find the exact solutions of the system</em>

equate equation A and equation B

$x^{2} +3x=2x+5\\x^{2} +3x-2x-5=0\\x^{2} +x-5=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-5=0$

so

$a=1\\b=1\\c=-5$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-5)}} {2(1)}$

$x=\frac{-1\pm\sqrt{21}} {2}$

so

The solutions are

$x_1=\frac{-1+\sqrt{21}} {2}$

$x_2=\frac{-1-\sqrt{21}} {2}$

<em>Find the values of y</em>

<em>First solution</em>

For $x_1=\frac{-1+\sqrt{21}} {2}$

$y=2(\frac{-1+\sqrt{21}} {2})+5$

$y=-1+\sqrt{21}+5\\\\y=4+\sqrt{21}$

The first solution is the point $(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$

<em>Second solution</em>

For $x_2=\frac{-1-\sqrt{21}} {2}$

$y=2(\frac{-1-\sqrt{21}} {2})+5$

$y=-1-\sqrt{21}+5\\\\y=4-\sqrt{21}$

The second solution is the point $(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$

Round to the nearest hundredth

<em>First solution </em>

$(\frac{-1+\sqrt{21}} {2},4+\sqrt{21})$ -----> $(1.79,8.58)$

$(\frac{-1-\sqrt{21}} {2},4-\sqrt{21})$ -----> $(-2.79,-0.58)$

see the attached figure to better understand the problem

6 0

3 years ago

Matt, the coordinator at the local emergency food hamper program, noticed the following trends: typically 200 hampers were distr

photoshop1234 [79]

Answer:

<em>793 food hampers were distributed</em>

Step-by-step explanation:

We need to find how many food hampers were distributed in a typical week, knowing that

200 hampers were distributed on Mondays

40 fewer hampers were distributed on Tuesdays than on Mondays, thus:

160 hampers were distributed on Tuesdays

on Wednesdays, the volume is 1.3 times Tuesday’s volume, thus 160*1.3=

208 hampers were distributed on Wednesdays

on Thursdays the number of hampers distributed was 3/4 of Monday’s volume, thus 3/4*200=

150 hampers were distributed on Thursdays

on Fridays, 50% of Thursday’s volume was distributed, therefore 50%*150=

75 hampers were distributed on Fridays

The total number of food hampers distributed in the week is

200+160+208+150+75=793

793 food hampers were distributed

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3 years ago

Which toy pack has a cost of $2.50 per toy?

defon

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3 years ago

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