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2 years ago

Find the inner product for (7, 2) * (0, -2) and state whether the vectors are perpendicular.

Mathematics

2 answers:

Kryger [21]2 years ago

5 0

Answer:

a) -4, no

Step-by-step explanation:

a•b = (x1 × x2) + (y1 × y2)

= (7 × 0) + (2 × -2)

= 0 - 4

= -4

Hence they are not Perpendicular

Andrews [41]2 years ago

3 0

Answer: A

Step-by-step explanation:

To find the inner product of two vectors (a,b) and (c,d) you would use the equation (a * c) + (b * d)

So for (7,2) and (0,-2) the inner product would be

(7 * 0) + (2 * -2)

= 4

The vectors are only perpendicular when the inner product is equal to 0. Since it is equal to -4 in this case, the vectors are not perpendicular.

A -4; no

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2 years ago

There are 6 red marbles 4 blue marbles to yellow marbles. Sabrina picks 2 marbles without putting the first one back what is the

Yanka [14]

Answer:

P = 3/11

Step-by-step explanation:

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6 red marbles

4 blue marbles

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2 years ago

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Gnom [1K]

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Since we have given that

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Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is $4x^2+1$

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2 years ago

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Thus, the answer is root 2.

Hope this helps :)</span>

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