The lengths of sides a and c add to 9 cm, the length of side b.
In a triangle, the the sum of the lengths of any two sides must be greater than the the length of the third side. These dimensions do not make a triangle.
Is this really what you meant? Why did you use capital A for a side? Or is A an angle, and it measures 6 deg, not 6 cm?
Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
If you mean 3 more terms in the sequence they could be
64, 32, 16, 8 ...
If you mean any 3 terms then 4096 1024 and 256 qualify.
Answer:
88
Step-by-step explanation:
Solve inside first
2^3=8
8+5= 13
Now multiply by 4
=52
Now by 2
=104
Now this is what we have left
=104-4^2
Make it easy by solving 4^2 which is 16.
104-16
=88
Answer:
Step-by-step explanation:
