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34kurt
3 years ago
8

the microsoft excel application is a _____ program. database word-processing spreadsheet desktop-publishing

Computers and Technology
1 answer:
irakobra [83]3 years ago
6 0
The correct answer is 'spreadsheet' 
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Why do you think fax machines use RLE?
Mashutka [201]

Answer:

Fax machines still use RLE for compressing the faxed documents, since they only need to represent black and white letters. JPEG images do use RLE during a final stage of compression, but they first use a more complex algorithm to compress the photographic details

8 0
3 years ago
Write a program that accepts as input the mass, in grams, and density, in grams per cubic centimeters, and outputs the volume of
rewona [7]

Answer:

Program for the above question in python:

mass = float(input("Enter the mass in grams")) # It is used to take the mass as input.  

density = float(input("Enter the density grams per cm cube")) # It is used to take the input for the grams.

print("Volume ={:.2f}".format(mass/density)) #It is used to print the Volume.

Output:

  • If the user inputs as 2.98 and 3.2, then it will results as 0.92.

Explanation:

  • The above code is in python language, in which the first statement is used to take the inputs from the user for the mass and sore it into a mass variable.
  • Then the second statement also takes the input from the user and store it into a density variable.
  • Then the third statement of the code is used to print the volume up to two places using the above-defined formula.
3 0
4 years ago
Write a recursive method that tests whether a string is a palindrome. It should return a boolean T or F depending on whether or
Sveta_85 [38]

Answer:

// program in java.

// library

import java.util.*;

// class definition

class Main

{

// recursive function to check palindrome

   public static boolean isPalin(String str){

// base case

     if(str.length() == 0 ||str.length()==1){

        return true;

     }

// if first character is equal to last

     if(str.charAt(0) == str.charAt(str.length()-1))

     {

     // recursive call

        return isPalin(str.substring(1, str.length()-1));

     }

     // return

     return false;

  }

  // main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // object to read input

Scanner scr=new Scanner(System.in);

System.out.print("Enter a string:");

 // read string from user

String myString =scr.nextLine();

 // call function to check palindrome

     if (isPalin(myString)){

        System.out.println("Given String is a palindrome");

     }

// if string is not palindrome

     else{

        System.out.println("Given String is not a palindrome");

     }    

   }catch(Exception ex){

       return;}

}

}

Explanation:

Read a string from user and assign it to variable "myString" with scanner object. Call the method isPalindrome() with string input parameter.In this method, if  length of string is 0 or 1 then it will return true(base case) otherwise it will call itself and compare first character with last character.If string is palindrome then function will return true else return false.

Output:

Enter a string:ababa                                                                                                      

Given String is a palindrome

8 0
4 years ago
Which of the following are vector graphic file formats? Choose all that apply.
ddd [48]

i need pics to see what it is



5 0
3 years ago
Consider a sequence of 1's and 1's with the property that the sum of any prefix of the sequence is never negative For example th
MrMuchimi

Answer:

Check the explanation

Explanation:

Answer: Solution: Algorithm:

Step 1: Start.

Step 2: Create a stack Step

3: Push an initial stack variable, it will represent that, stack is empty.

Step 4: Get input

             If +1 then push "+1"

             Else if -1 then pop

Step 5: Repeat until all input finish or Stop if empty stack variable popped. Step 6: Stop.

It is a pushdown automata problem.

It can be also represented as:

X =1+1* —1* 1No(+1)>= No(-1)}

4 0
3 years ago
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