Answer:
The common difference is
or 0.2
Step-by-step explanation:
Given:
Arithmetic Sequence -2, -1 4/5, -1 3/5, -1 2/5,
First term = a₁ = -2
Second term = a₂ = 
Third term = a₃ = 
Fourth term = a₄ = 
To Find:
Common Difference = d = ?
Solution:
Formula for Common Difference d ,

∴ 
The common difference is
or 0.2
Answer:
Common factor
Factor by grouping
Factor by grouping
−
2
−
2
+
1
-x^{2}-2x+1
−x2−2x+1
−
1
(
2
+
2
−
1
)
{\color{#c92786}{-1(x^{2}+2x-1)}}
−1(x2+2x−1)
Solution−
-1(x²+ 2x-1 )
Answer:
hundreaths
Step-by-step explanation:
if you count on the right side of the decimal each time you count it goes tenths, hundreaths, thousandths, etc. the 5 is 2 places on the right of the decimal so therefore it is hundreaths
I'm assuming the function is f(x) = (2x+8)/(x^2+5x+6). If so, make sure to use parenthesis to indicate that you're dividing all of "2x+8" over all of "x^2+5x+6" as one big fraction. Otherwise, things are ambiguous and it leads to confusion.
Side Note: x^2 means "x squared"
Factor the numerator: 2x+8 = 2(x+4)
Factor the denominator: x^2+5x+6 = (x+2)(x+3)
There are no common factors between the numerator and denominator. So there is nothing to cancel out.
Recall that you cannot divide by zero. Something like 1/0 is undefined.
We need to find the x values that cause the denominator to be zero.
Set the denominator equal to zero and solve for x
x^2+5x+6 = 0
(x+2)(x+3) = 0
x+2 = 0 or x+3 = 0
x = -2 or x = -3
The x values x = -2 or x = -3 will lead to the denominator being zero. This means that the vertical asymptotes are x = -2 or x = -3 as shown by the blue dashed vertical lines in the attached image.