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Naddik [55]
3 years ago
8

∠A and ∠B are complementary angles. The measure of ∠A=4x° and the measure of ∠B=50°. Find m∠A. * i dont understand can someone h

elp?
Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

m>a is 40

Step-by-step explanation:

4x + 50 = 90

4x = 40

x = 10

10*4 = 40

M>A = 40

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Solve for x <br> 2(3x + 7) = 5 + 6x
Ira Lisetskai [31]

Answer:

x = − 4 − √ 466 , − 4 + √ 46   6   Decimal Form:   x  =  0.46372166 … ,   − 1.79705499 …

Step-by-step explanation:

3 0
3 years ago
Solve the following exponential equations.<br> 10^(3x−5) = 7^x
zalisa [80]

Answer:

x = 2.3202

Step-by-step explanation:

Given equation:

10^{(3x-5)} = 7^x

on taking log both sides, we get

\log(10^{(3x-5))} =\log(7^x)

now,

using the property of log function

log(aᵇ) = b × log(a)

therefore,

we get

(3x-5)log(10) = xlog(7)

now,

log(10) = 1

and

log(7) = 0.84509

thus,

( 3x - 5 ) × 1 = 0.84509x

or

3x - 0.84509x - 5 = 0

or

2.15491x = 5

or

x = 2.3202

4 0
3 years ago
Alfonso and Lucas are 238 miles apart, traveling towards each other. If Lucas travels 21 mph and Alfonso travels 13 mph how long
Alex

Lucas equation for his location is x(t) = 13t.

Alfonso's equation is x(t) = 238 - 21t

If you equate these, you get:


13t = 238 - 21t =>

34t = 238

t = 7


So after seven hours they meet.

7 0
3 years ago
Someone please help :)
larisa86 [58]
The answer is 6m djsjdjjsskskksksksksksksmsmsm
8 0
3 years ago
find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS
charle [14.2K]

Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

8 0
3 years ago
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