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Lisa [10]
3 years ago
5

A leaking pond loses 20 gallons of water in 49 hours. How many gallons of water will it lose in 5 hours? Round to one decimal pl

ace
Mathematics
2 answers:
White raven [17]3 years ago
5 0

Answer:

12.25

Explanation

49/20 <em><u>(which is the same as (</u></em><em><u>4</u></em><em><u>9</u></em><em><u>÷</u></em><em><u>2</u></em><em><u>0</u></em><em><u>))</u></em><em><u> </u></em>=2.45

<em><u>Multiply</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em><em><u>5</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>hours</u></em><em><u> </u></em><em><u>(</u></em><em><u>5</u></em><em><u>)</u></em><em><u> </u></em>

2.45 \times 5 = 12.25

=12.25

inessss [21]3 years ago
4 0

Answer:it will lose 2 gallons of water in 5 hours.

Step-by-step explanation:

A leaking pond loses 20 gallons of water in 49 hours. This means that the number of gallons of water that the pond will leak in one hour would be

20/49 gallons per hour.

Therefore, the number of gallons of water that the pond will lose in 5 hours would be

20/49 × 5 = 2.0408 gallons

Rounding to one decimal place, it becomes 2 gallons

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