A leaking pond loses 20 gallons of water in 49 hours. How many gallons of water will it lose in 5 hours? Round to one decimal pl ace
2 answers:
Answer:
1 2 . 2 5
Explanation
49 / 2 0 <em><u>(which is the same as (</u></em><em><u>4</u></em><em><u>9</u></em><em><u>÷</u></em><em><u>2</u></em><em><u>0</u></em><em><u>))</u></em><em><u> </u></em>= 2 . 4 5
<em><u>Multiply</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em><em><u>5</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>hours</u></em><em><u> </u></em><em><u>(</u></em><em><u>5</u></em><em><u>)</u></em><em><u> </u></em>
= 1 2 . 2 5
Answer:it will lose 2 gallons of water in 5 hours.
Step-by-step explanation:
A leaking pond loses 20 gallons of water in 49 hours. This means that the number of gallons of water that the pond will leak in one hour would be
20/49 gallons per hour.
Therefore, the number of gallons of water that the pond will lose in 5 hours would be
20/49 × 5 = 2.0408 gallons
Rounding to one decimal place, it becomes 2 gallons
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