There are many different fractions that cannot be simplified with a 24 as the denominator! A few examples include:
1/24
5/24
7/24
33/24
107/24
Notice all of the numerators are prime.
These numbers are 12 and 14.
jeez that looks really hard
Step-by-step explanation:
In the ordered pair (2, 12), x = 2 and y = 12.
Substitute these values into each inequality to see if the resulting inequality is true.
y > 2x + 4
12 > 2(2) + 4 Twelve is greater than 2 times 2 plus 4 ...hmmm
12 > 4 + 4
12 > 8 Twelve is greater than 8 ....this is TRUE...go to the next inequality
y < 3x + 7
12 < 3(2) + 7 Twelve is less than 3 times 2 plus 7 ...interesting
12 < 6 + 7
12 < 13 Twelve is less than 13 ... this is TRUE also
Therefore; the answer is b. Yes
It must create a true inequality for BOTH inequalities in order for the ordered pair to be a solution
No
A chord is a straight sediment that joins two points of the circumference. The radius goes from the center of the circle, which is not on the radius.
