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34kurt
3 years ago
4

Olga tried to solve an equation step by step

Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0

Answer:

made a mistake in step 3

Step-by-step explanation:

from step2; 1/3k=15 then making k the subject ,k=15*3 so the value of k will be 45

sladkih [1.3K]3 years ago
8 0

Answer:

step 3

Step-by-step explanation:

she should have multiplied 15 x 3=45

k=45

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Evaluate 3x+y when x=1/3 and y=−7/4. Write your answer as a fraction in simplest form.
SOVA2 [1]

Answer:

3x+y

=3*1/3-7/4

=1-7/4

=(4-7)/4

=-3/4

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3 years ago
Lorena is driving a truck that is painting the lines on a new road. The lines she paints are 0.152 meters wide, and she will pai
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Answer:

  8.284 × 10^4 m^2

Step-by-step explanation:

The area is the product of length and width:

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4 years ago
Whích situation can be modeled by the inequality 50 – 12. > 8?
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Step-by-step explanation:

8 0
3 years ago
A professor has recorded exam grades for 10 students in his​ class, but one of the grades is no longer readable. If the mean sco
Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

\frac{R+x}{10} =80

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

\frac{R}{9} = 85\\ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

\frac{R}{9} = 85\\R=85*9= 765

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35

4 0
3 years ago
What are 25 equations using integers that equal 36?
salantis [7]
36 + 0 = 36, 35 + 1 = 36, 34 + 2 = 36, 33 + 3 = 36, 36 - 0 = 36, 37 - 0 = 36, 38 - 2 = 36, 39 - 3 = 36, 2 + 34 = 36, 4+ 32 = 36, 6 + 30 = 36
8 0
3 years ago
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