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bearhunter [10]
3 years ago
8

PLEASE! PLEASE! help!

Mathematics
1 answer:
qaws [65]3 years ago
4 0
1.) The answer is 825.75 (multiply the given tax rates to the gross pay)
    2,785 x 13% federal taxes = 362.05
    2,785 x 9% state tax         = 250.65
    2,785 x 7.65% FICA          = <u>213.05
</u>                                                 825.75
<u>
</u>2.) The answer is 288.60 (multiply the interest rate to the balance, no need to add a late payment fee since they paid on 6/1, not after)
    2,748.56 x 10.5% = 288.60

3.) The answer is 182.13  (multiply the APR to the original purchase price, no need to add the sales tax)
<u />    1,500 x 11.75% = 182.13

4.) The answer is 371.92 (deduct the reward to the interest)
    Interest : 2,975.34 x 13.5% = 401.67
    Reward : 2,975.34 x 1%      = <u>  29.75</u>  
                                                    371.92

5.) The answer is  1,339.13 (deduct the interest to the monthly payment)
    Monthly payment : 2,236.00
    Monthly interest :   <u>   896.87</u> [(231,450 x 4.65%) / 12 months]
<u />                                    1,339.13

Hope this helps! :)
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in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

the proportion is

p = 154/200 = 0.77

<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

<em>Mean </em>

p = 0.77

<em>Standard deviation </em>

\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298

The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0
3 years ago
Jesse needs 10 1/4 feet of chain to complete an outdoor project. He has two small pieces each measuring 2 1/8 feet and a third p
Effectus [21]

Answer:

= 2 1/4 feet

Step-by-step explanation:

Length of chain Jesse needs = 10 1/4 feet

Length of chain Jesse has:

Two small pieces each measuring 2 1/8 feet

= 2 × 2 1/8 feet

= 2 × 17/8

= 34/8 feet

Third piece measuring 3 3/4 feet

Total Length of chain Jesse has = 34/8 feet + 3 3/4 feet

= 34/8 + 15/4

= 34+30/8

= 64/8

= 8 feet

Total Length of chain Jesse has = 8 feet

Length of chain Jesse needs to purchase = Length of chain Jesse needs - Total Length of chain Jesse has

= 10 1/4 feet - 8 feet

= 2 1/4 feet

Length of chain Jesse needs to purchase = 2 1/4 feet

7 0
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