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3 years ago

There are 39 students in Ms. Salazar's chemistry class. If Ms. Salazar divides the class into 9 lab

Mathematics

1 answer:

belka [17]3 years ago

5 0

Answer:

Number of lab group with 5 students = 3

Thank you

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1.9% as a decimal it’s for math class

Arada [10]

Answer:

0.019

Step-by-step explanation:

btw instead of wasting points you can look that up on g*oogle, goo*gle has a calculator that will help you find out decimals and percent's!

pieces of advice

can i have brainliest?

5 0

2 years ago

Read 2 more answers

Marta bought 3 towels for $8.50 each and 5 washcloths for $1.25 each. If the sales tax rate is 8%, what is the total amount of m

kap26 [50]

Answer:

$32.25

Step-by-step explanation:

3 × $8.50 = $25.50, 5 × $1.25 = $6.25 × sales tax (8%) = $0.50, $6.25 + $25.50 + $0.50 = $32.25

6 0

2 years ago

(28 POINTS) write the next three terms in the sequence.

blondinia [14]

Answer:

25, 34, 43

Step-by-step explanation:

its +9 per number

5 0

3 years ago

There are 100 equally spaced points around a circle. At 99 of the points, there aresheep, and at 1 point, there is a wolf. At ea

rewona [7]

Answer:

we have $p_{51} = \frac{1}{100}$

Step-by-step explanation:

considering circle with 100 points on it and then placing the wolf on one and sheep on rest.

pi = P( sheep on i-th spot is eaten at last}

As in the question we need to find probability of sheep opposite to the wolf, so p_{51}. observe each last spot is replaced by i-1 after eating

Byy LOTP we know thta $pi = \frac{1}{2}pi-1 + \frac{1}{2}pi + 1, i \epsilon {2,... 99}$

also these pi need to satisfy

$\sum_{i=1}^{100} pi =1$

some sheep is eaten at last. Distribution is

$pi = \frac{1}{100}$

satisfies above equation, therefore we have $p_{51} = \frac{1}{100}$

6 0

2 years ago

Find the sum of the first 30 terms in the sequence in #2. (Sequence is 16, 7, -2, …) Just need sum of first 30 solved :)

Romashka [77]

The sequence is arithmetic, since the forward difference between consecutive terms is -9.

7 - 16 = -9

-2 - 7 = -9

etc.

This means the sequence has the formula

$a_n=16-9(n-1)=25-9n$

The sum of the first 30 terms is

$\displaystyle\sum_{n=1}^{30}a_n=25\sum_{n=1}^{30}1-9\sum_{n=1}^{30}n$

Recall the formulas,

$\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n$

$\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2$

Then the sum we want is

$\displaystyle\sum_{n=1}^{30}a_n=25\cdot30-\frac{9\cdot30\cdot31}2=\boxed{-3435}$

5 0

3 years ago