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3 years ago

There are 39 students in Ms. Salazar's chemistry class. If Ms. Salazar divides the class into 9 lab

Mathematics

1 answer:

belka [17]3 years ago

5 0

Answer:

Number of lab group with 5 students = 3

Thank you

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2 1/2+x=5 1/3 PLEASE HELP

erastova [34]

Answer:

Step-by-step explanation:

2 1/2 + x = 5 1/3 Change the mixed numbers to improper fractions

5/2 + x = 16/3 The lowest common multiple is 6. Multiply by 6

5*3 + 6x = 16*2

15 + 6x = 32 Subtract 15 from both sides.

6x = 32 - 15

6x = 17 Divide by 6

6x/6 = 17/6

x = 2 5/6

Check

5/2 + 17/6 = 16/3

15/6 + 17/6 = 32/6

32/6 = 32/6 The question checks.

7 0

2 years ago

If m∠JKP=3r+12 and m∠2=4r−2, what is ∠JKN?

Leokris [45]

The answer seems to be 108

8 0

3 years ago

10 plus 10 divided and rounded to next 20

BartSMP [9]

10.5 I looked it up OKAY

7 0

3 years ago

Find the area of each figure

Anon25 [30]

Area of trapezoid = a + b/2 * h
a = 20, b = 9, h = 21/-16
20+9/2 * (21-16) = 29/2 * 5 = 72.5
The area of the trapezoid = 72.5 in^2

Area of the rectangle = l * w
l = 16, w = 20
16 * 20 = 320
The area of the rectangle: 320 in^2

7 0

3 years ago

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

3 0

3 years ago