Y>x−4 y\ge -\frac{1}{2}x+5 y≥− 2 1 x+5

serious [3.7K]

8 (3g+2)-3g=3 (5g-4)-2
Multiply the number outside the exponent with the numbers inside the parenthisis.
24g+16-3g=15g-12-2
Subtract 3g from 24g
21g+16=15g-12-2
Add 15g to 21g
36g+16=-12-2
Subtract 2 from -12
36g+16=-14
Subtract 16 from -14
36g=30
Final Answer: g=0.83 (The three goes on infinitely.)

7 0

3 years ago

What is the the total cost of a book that is $45.60 with a sales tax of 7.5%

sineoko [7]

3.42 multiply 45.60 by 0.075

6 0

3 years ago

The ratio of tomatoes to pepper plants in the garden is 5:2. If there are 6 more tomato plants than pepper plants, how many pepp

Kay [80]

The ratio from tomatoes to pepper plants is 5:2

Meaning there are 5 tomatoes and 2 pepper plants

In order to find a ratio where there are 6 more tomatoes than pepper plants you will have to multiply.

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When the ratio 5:2 is multiplied by 2

it equals 10:4

We can stop here because it is shown that now there are 6 more tomatoes than pepper plants.

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So there are:

10 tomatoes

and

4 pepper plants!

6 0

3 years ago

How many hours did jacoboys drive on Monday and Tuesday and in all?

melomori [17]

Looks like 10 and and a half if it's four it's 10 and a half if it 6 it's 12 and a half

7 0

3 years ago

1)How many ways can the letters in the word BOOKKEEPER be arranged? (Must show set-up )

sergeinik [125]

Question 1

There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are $\frac{10!}{(10-6)!6!}$ ways of arranging the letters, which equal to 210 ways

Question 2

There are seven swimmers in total.
There are $\frac{7!}{(7-1)!1!}$ ways of choosing the first winner, which is 7 ways
There are $\frac{6!}{(6-1)!1!}$ ways of choosing the second winner, which is 6 ways
There are $\frac{5!}{(5-1)!1!}$ ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner

Question 3

The probability of eating an orange and a red candy is $\frac{15}{31}$ × $\frac{9}{30}$ , which equals to $\frac{9}{62}$

The probability of eating two green candies is $\frac{7}{31}$ × $\frac{6}{30}$ which equals to $\frac{7}{155}$

3 0

3 years ago

Y>x−4 y\ge -\frac{1}{2}x+5 y≥− 2 1 ​ x+5

Y>x−4 y\ge -\frac{1}{2}x+5 y≥− 2 1 x+5