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3 years ago

Determine the value of y, if x is 5. y= (x +3 Answer: Submit Answer

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

6 0

The value of y is 8! 5+3=8

zepelin [54]3 years ago

4 0

Answer:

y=8

Step-by-step explanation:

substitute (plug in) 5 for x because it says that the value of x is 5

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Peytons car used 6 gallons to travel 192 miles how many gallons of gas would she need t I travel 480 miles

ELEN [110]

Answer:

15 gallons

Step-by-step explanation:

if 6gallons = 192 miles

then x gallons 480 miles

x = (6*480)/192

x = 2880/192

x = 15 gallons

5 0

3 years ago

Consider the power 34.

Vikentia [17]

I believe it’s 3 to the 34 power

4 0

3 years ago

A zookeeper predicted the weight of a new baby elephant to be 230 pounds when I was born the elephant actually weigh 262 pounds

insens350 [35]

Answer:

13.9%

Step-by-step explanation:

Given data

Expected weight = 230 pounds

Actual weight= 262 pounds

Required

The percent error

Error= Actaul- expected/ expected *100

Error= 262-230/230*100

Error=32/230*100

Error=0.139*100

Error=13.9%

Hence the error is 13.9%

5 0

2 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

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Soloha48 [4]

Desert Shores is below the sea level and the difference is more than 600 feet

4 0

3 years ago