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Alex Ar [27]
3 years ago
6

SHOW WORK: Evaluate f(-2) f(x)= 3/2x-4​

Mathematics
2 answers:
katrin [286]3 years ago
7 0

Answer:

f(-2)=-5

Step-by-step explanation:

f(-2) = 3/2(-2) -4

f(-2)= -3-2

f(-2)= -5

Anarel [89]3 years ago
3 0

Answer:

f=-3/4x+2

Step-by-step explanation:

f(−2)=3/2x−4

−2f/−2=3/2x−4/−2

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The simple interest charged on a 65-day loan of $1,290 is $5.75. Find the annual simple interest rate (in percent) for this loan
Elan Coil [88]

Answer:

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

P represents the principal or initial amount invested or collected as a loan.

R represents interest rate.

T represents the duration of time in years before the loan is bald back.

From the information given,

P = 1290

I = 5.75

Since there are 365 days in a year,

t = 65/365 = 0.1781 years

Therefore,

5.75 = (1290 × r × 0.1781)/100

5.75 = 229.749r/100 = 2.29749r

r = 5.75/2.29749

r = 2.5027

Rounding to the nearest percent,

r = 3%

5 0
3 years ago
Read 2 more answers
summer break is almost around the corner. You and your family call an uber and need to know how many miles you can be driven. Ub
Alex777 [14]

Answer:

You can go 26 miles

Step-by-step explanation:

15 - 1 = 14

14 ÷ 0.52 = 26.92

4 0
3 years ago
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
Write the decimal 1.822 as a fraction. Do not write in lowest terms.
Degger [83]
Answer to your problem is:

1 411/500

I believe XD.
5 0
3 years ago
Simplify each expression. Use positive exponents. <br> A^4b^-3<br> ab^-2
choli [55]
\dfrac{a^4b^{-3}}{ab^{-2}}

= {a^{4-1}b^{-3+2}}

= {a^{3}b^{-1}}

= \dfrac{a^3}{b}


6 0
3 years ago
Read 2 more answers
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