For this question you have to solve the equation backwards.
A = 1/2 x (b1 + b2) x h
In order to get rid of the 1/2 (since it's division) multiply each side by 2
now we have: 2A = (b1 + b2) x h
Now do the same to the get rid of the (b1 + b2) (divide each side by it)
2A/(b1 + b2) = h
First question
1:C 2:D 3:B 4:D
second question
0-2+5
Answer:
The answer is:
A. It is in the quadrants I and III.
Step-by-step explanation:
I am not sure if this is correct, but I tried my best :)
I hope this helped~
The area of the shaded region is going to be the area of the rectangle minus the area of the square.
Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle
area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1
now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.
2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
x^2 + 23x + 49 <== the area of the shaded region
