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UkoKoshka [18]
3 years ago
9

Point P'(-3, 2) is the image of point P(3, 8) under a translation. What is the image of (0, -6) under the

Mathematics
1 answer:
Goshia [24]3 years ago
5 0

Answer:

The image of the point (0, -6) under the same translation is (-6, -12)

Step-by-step explanation:

Let us revise the rules of translation

  • If the point (x, y) translated horizontally to the right by h units then its image is (x + h, y) ⇒ T (x, y) → (x + h, y)
  • If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)
  • If the point (x, y) translated vertically up by k units then its image is (x, y + k)→ (x + h, y) ⇒ T (x, y) → (x, y + k)
  • If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)

∵ The coordinate of point P are (3, 8)

∵ The coordinates of its image P' are (-3, 2)

→ The x-coordinate is changed from 3 to -3, that means the point

   translated to the left by h units

∵ h = -3 - 3

∴ h = -6

→ The y-coordinate is changed from 8 to 2, that means the point

   translated down by k units

∵ k = 2 - 8

∴ k = -6

→ By using the rule above

∴ The rule of translation is (x, y) → (x - 6, y - 6)

∵ The coordinates of the point are (0, -6)

∴ The coordinates of its image are (0 - 6, -6 - 6)

∴ The coordinates of its image are (-6, -12)

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\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

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Step-by-step explanation:

Given -

Mean (\nu )  = 4

Standard deviation (\sigma  ) = 1.5

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proportion of the trees will have diameters between 2 and 6 inches =

P(2<  X<  6)   =  P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}<  \frac{6 - 4 }{1.5})

                         = P(\frac{-2 }{1.5}< Z<  \frac{2 }{1.5})     Put  [Z = \frac{X - \nu }{\sigma}]

                         =  P(-1.33< Z<  1.33)

                          = (Z<  1.33) - (Z<  -1.33)

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Read 2 more answers
. At a clothing store, 12 people purchased blue sweaters, 8 purchased green sweaters, 4 purchased gray sweaters, and 7 purchased
DedPeter [7]

Answer:

The probability that they purchased a green or a gray sweater is \frac{12}{31}

Step-by-step explanation:

Probability is the greater or lesser possibility of a certain event occurring. In other words, probability establishes a relationship between the number of favorable events and the total number of possible events. Then, the probability of any event A is defined as the quotient between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law.

P(A)=\frac{number of favorable cases}{number of possible cases}

The addition rule is used when you want to know the probability that 2 or more events will occur. The addition rule or addition rule states that if we have an event A and an event B, the probability of event A or event B occurring is calculated as follows:

P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

P (A): probability of event A occurring.

P (B): probability that event B occurs.

P (A⋃B): probability that event A or event B occurs.

P (A⋂B): probability of event A and event B occurring at the same time.

Mutually exclusive events are things that cannot happen at the same time. Then P (A⋂B) = 0. So, P(A∪B)= P(A) + P(B)

In this case, being:

  • P(A)= the probability that they purchased a green sweater
  • P(B)= the probability that they purchased a gray sweater
  • Mutually exclusive events

You know:

  • 8 purchased green sweaters
  • 4 purchased gray sweaters
  • number of possible cases= 12 + 8 + 4+ 7= 21

So:

  • P(A)=\frac{8}{31}
  • P(B)=\frac{4}{31}
  • P(A⋂B) = 0

Then:

P(A∪B)= P(A) + P(B)

P(A∪B)= \frac{8}{31}+ \frac{4}{31}

P(A∪B)= \frac{12}{31}

<u><em>The probability that they purchased a green or a gray sweater is </em></u>\frac{12}{31}<u><em></em></u>

5 0
3 years ago
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