Answer:
t = 0.67635 s
n = 6764
Explanation:
Given:
- The velocity of sound in water v:
v = √(B/rho)
Where, B: Bulk Modulus = 2.28*10^9 Pa
rho: Density of salt water = 1043 kg/m^3
- The wale sends out a high frequency f = 10 kHz
- The distance between two wales s = 1.0 km
Find:
- Time taken for the sound to travel between whales t?
- How many wavelengths can fit between the two whales n?
Solution:
- The time taken for the sound to travel from one whale to another can be determined from:
t = s / v
t = s / √(B/rho)
t = s*√(rho/B)
- Plug in the values:
t = 1000*√(1043/2.28*10^9)
t = 0.67635 s
- The wavelength λ of the sound emitted can be calculated by the following formula:
λ = √(B/rho) / f
λ = √(2.28*10^9/1043) / 10^4
λ = 0.14785 m
- The number of wavelengths n that could fit in the distance s is:
n*λ = s
n = 1000 / 0.14785
n = 6764