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defon
3 years ago
5

Sound in water travels at a velocity governed by the relation v = √(B/rho) where B is the bulk modulus and rho is the density. F

or salt water, take B = 2.28 × 109 Pa and rho = 1043 kg/m3. A whale sends out a high frequency (10 kHz) song to another whale 1.0 km away.
Physics
1 answer:
12345 [234]3 years ago
4 0

Answer:

t = 0.67635 s

n = 6764

Explanation:

Given:

- The velocity of sound in water v:

                                    v = √(B/rho)

Where, B: Bulk Modulus = 2.28*10^9 Pa

            rho: Density of salt water = 1043 kg/m^3

- The wale sends out a high frequency f = 10 kHz

- The distance between two wales s = 1.0 km

Find:

- Time taken for the sound to travel between whales t?

- How many wavelengths can fit between the two whales n?

Solution:

- The time taken for the sound to travel from one whale to another can be determined from:

                               t = s / v

                               t = s / √(B/rho)

                               t = s*√(rho/B)

- Plug in the values:

                               t = 1000*√(1043/2.28*10^9)

                              t = 0.67635 s

- The wavelength λ of the sound emitted can be calculated by the following formula:

                               λ = √(B/rho) / f

                               λ = √(2.28*10^9/1043) / 10^4

                               λ =  0.14785 m

- The number of wavelengths n that could fit in the distance s is:

                               n*λ = s

                               n = 1000 / 0.14785

                              n = 6764

                               

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A vacuum cleaner has a rating of 460 W on 230 V mains. The value of the fuse connected in the plug will be
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A mass of 4kg suspended by a light string 2m long and at rest is projected horizontally with a velocity of 1.5 m/s. find the ang
Dafna11 [192]

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19.5°

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Let the height at the lowest point of the be h=0, the energy of the mass will be:

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The energy when the mass comes to a stop will be:

3) E=mgh

Setting equations 2 and 3 equal and solving for height h will give:

4) h=\frac{v^2}{2g}

The angle ∅ of the string with the vertical with the mass at the highest point will be given by:

5) cos\phi=\frac{l-h}{l}

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8 0
3 years ago
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Natali5045456 [20]
From Newton's second law of motion, it is identified that the net force applied to the object with mass m, will make it move with an acceleration of a. This can be mathematically translated as,
                        F = m x a
To solve for the mass of the sled, we derive the equation above such that,
                        m = F / a
Substituting,
                       m = (18 N) / (0.39 m/s²)
                          m = 46.15 kg

Then, we add to the calculated mass the mass of the extra material.
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We solve for the normal force of the surface to the object by calculating its weight.
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The force that would allow barely a movement for the object is equal to the product of the normal force and the coefficient of kinetic friction.
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                      c = F/F₂

Substituting,
                      c = 18 N/496.41 N
                       c = 0.0362

<em>ANSWER: c = 0.0362</em>

5 0
2 years ago
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