All categories

3 years ago

What is the maximum velocity at which a 60-watt motor can lift an 8.5-kg mass upward?

Physics

1 answer:

enyata [817]3 years ago

3 0

Pick choice-A .

Weight of a mass = (mass) x (gravity)

Earth gravity = (9.8 m/s )

Weight of a mass = (9.8 x mass) Newtons

Work = (force) x (distance)

Power = (work done) / (time to do the work)

Weight of this mass = (8.5 kg) x ( 9.8 m/s ) = 83.3 Newtons

Work to lift it 1 meter = (83.3 N) x (1 m) = 83.3 Joules

Power to lift it 1 meter/sec = 83.3 Joule/sec = 83.3 watt

Power to lift it ' v ' meters/sec = 83.3v watts

In this problem ...

83.3 v watts = 60 watts

v = 60/83.3 m/s

v = 0.72 m/s

You might be interested in

A boat has a mass of 31,999 kg and a plane has a mass of 110,000 kg. What is the ratio of weight of the plane to the boat?

Gelneren [198K]

Answer:

3.44:1

Explanation:

We use ratios to find the ratio of weight.

Mass of Plane= 110000 kg ∴ W= mg

Mass of Boat =31999 kg

$\frac{weight of plane}{weight of boat}$ = $\frac{110000*9.81}{31999*9.81}$

= $\frac{3.44}{1}$

SO 3.44:1

8 0

4 years ago

Read 2 more answers

. What is the kinetic energy of a 10 kg car that is moving 4 m/s?

Darya [45]

Answer:i belive the answer is E = 1/2 mv^2

hope this helps plz mark me as braliest

8 0

3 years ago

Over a span of 6.0 seconds, a car changes it's speed from 89 km/h to 37 km/h. What is its average acceleration in meters per sec

scoundrel [369]

Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) - (speed at the beginning)

change in speed = (37 km/hr) - (89 km/hr) = -52 km/hr

Acceleration = (-52 km/hr) / (6 sec)

Acceleration = (-26/3) km/(hr·sec)

Units: (1/hr·sec) · (hr/3600 sec) = 1 / 3600 sec²

(-26/3) km/(hr·sec) = (-26/3) km/(3600 sec²)

= -26,000/(3 · 3600) m/s²

Acceleration = -2.41 m/s²

3 0

4 years ago

Vladimir [108]

Answer:

C. Resist change in motion.

Explanation:

Inertia: the tendency of an object to resist a change in motion unless an outside force acts on the object.

8 0

3 years ago

Read 2 more answers

If two firecrackers produce a sound level 85dB. What level does the explosion of one firecracker produce?

mars1129 [50]

Level of sound is related to intensity by this equation

$L = 10 Log \frac{I}{I_o}$

given that

L = 85 dB

also we know that

$I_o = 10^{-12} W/m^2$

now we have

$85 = 10 Log \frac{I}{10^{-12}}$

By solving above equation

$I = 10^{8.5} * 10^{-12}$

$I = 3.16 * 10^{-4} W/m^2$

now above is the intensity due to two firecrackers and if we wish to find the sound level of one firecracker then we will find its half level intensity

$I_1 = \frac{I}{2}$

$I_1 = 1.58 * 10^{-4}$

now again by above formula

$L = 10 Log \frac{1.58 * 10^{-4}}{10^{-12}}$

$L = 82 dB$

8 0

3 years ago