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3 years ago

Choose all of the true statements regarding the relationship between voltage, resistance, and current.

Physics

2 answers:

never [62]3 years ago

7 0

Answer:

Explanation:

PA HELP MA

bearhunter [10]3 years ago

5 0

Answer:

okay it's nun of ur bussiness love

Explanation:

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What is the density of a block of wood with a mass of 120 g and a volume of 200 cm

creativ13 [48]

D=m/V therefore the answer is 120/200 or 0.6

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3 years ago

A 500 kg wrecking ball is knocking down a wall. When it is pulled back to its highest point, it is at a height of 6.2 m. When it

svetlana [45]

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3 years ago

Find the magnitude of the electric field due to a charged ring of radius "a" and total charge "Q", at a point on the ring axis a

34kurt

Answer:

E= $\frac{KQ}{2\sqrt 2a^2}$

Explanation:

We are given that

Charge on ring= Q

Radius of ring=a

We have to find the magnitude of electric filed on the axis at distance a from the ring's center.

We know that the electric field at distance x from the center of ring of radius R is given by

$E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}$

Substitute x=a and R=a

Then, we get

$E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}$

$E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}$

$E=\frac{KQa}{2\sqrt 2a^3}$

$E=\frac{KQ}{2\sqrt 2a^2}$

Where K= $9\times 10^9 Nm^2/C^2$

Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center= $\frac{KQ}{2\sqrt 2a^2}$

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3 years ago

How do you calculate average speed?

Mila [183]

Divide
(the distance covered in some period of time)
by
(the time taken to cover the distance).

The quotient is the average speed during that period of time.

4 0

3 years ago

Read 2 more answers

I REALLY NEED HELP WITH PHYSICS ASAP!!!<br>Vf^2 = v0^2 + 2a (xf - x0)<br><br><br>Solve for a

ELEN [110]

Answer:

a. solve for a

$vf ^{2} = vo ^{2} + 2a(xf - xo) \\ 2a(xf - xo) = vf^{2} - vo ^{2} \\ a = \frac{vf^{2} - vo^{2} }{2(xf - xo)} \\ a = \frac{vf ^{2} - vo ^{2} }{2xf - 2xo}$

I hope I helped you ^_^

7 0

3 years ago