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Tatiana [17]
3 years ago
15

Tara is using matrix multiplication to find image points of a translation. She is translating the image 2 units left and 4 units

up. Which should be her first matrix?
Mathematics
1 answer:
Ahat [919]3 years ago
7 0
Assuming that this is just on a 2-D coordinate plane, we must convert the expressions on to a 3-D plane since translation cannot be done on a 2-D plane. This is done by adding a dummy coordinate that does not change. Let us use "1" for this case.

Matrix:
| 0 0 -2 |(x) = (x - 2)
<span>| 0 0 4  |(y) = (y + 4)
</span><span>| 0 0 1  |(1) = 1</span>
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3/4 of 9.3

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3 years ago
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Brilliant_brown [7]

Answer:

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Suppose that y varies inversely with x and y = 3 when x=10 find y when x=5
zysi [14]

Answer:

y=1.5

Step-by-step explanation:

if (y = 3) is  (x = 10) and (y = ?) is (x = 5) we see that x is half of the first equation in the second. This means we divide both variables in the first equation by half to get the second. [(x = 10) / 2 = (x = 5)] therefor, [(y = 3) / 2 = (y = 1.5)]. Making your answer 1.5.

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4 0
3 years ago
? A mug can hold 13.46 oz of coffee without overflowing. The radius of the mug is 3 cm. Given that 1 cm3 equals 0.034 oz, what i
Elan Coil [88]

Answer:

14 cm

Step-by-step explanation:

Given:

A mug can hold 13.46 oz of coffee.

The radius of the mug is 3 cm.

Given that 1 cm^{3} equals 0.034 oz.

Question asked:

What is the height of the mug to the nearest centimeter ?

Solution:

Given that 1 cm^{3} equals 0.034 oz.

By unitary method:

0.034 oz = 1 cm^{3}

1 oz = \frac{1}{0.034}

13.46 oz = \frac{1}{0.034}\times13.46 =395.88 \ cm^{3}

A mug can hold 13.46 oz of coffee means volume of cylinder is given which is 395.88 cm^{3}. Now we can find the height of the mug by using volume of cylinder formula:

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By cross multiplication:

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By dividing both side by 198

h = 13.99 cm

Therefore,  height of the mug to the nearest centimeter is 14 cm.

                   

6 0
3 years ago
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Setler79 [48]

Answer:

The first choice

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the base is 10 and height is 24

26 is the hypotenuse but it is not used in calculating the area

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