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rodikova [14]
2 years ago
9

ENERG

Physics
2 answers:
Romashka [77]2 years ago
6 0
Answer: B) Uranium

Fossil fuels are natural fuels that were formed from the buried remains of living organisms that lived millions of years ago. Uranium is not a fossil fuel, but it is considered as a nonrenewable fuel.
ladessa [460]2 years ago
5 0

Answer:

Uranium

Explanation:

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A 75-hp compressor in a facility that operates at full load for 2500 h a year is powered by an electric motor that has an effici
stealth61 [152]

Answer:

C = 16544.35\, USD

Explanation:

The annual electricity cost is:

C = (\frac{1}{0.93} )\cdot(75\, h.p.)\cdot(0.746\, kW)\cdot(2500\,h)\cdot(\frac{3600\,s}{1\,h} )\cdot(\frac{1\,kWh}{3600\,kJ} )\cdot (0.11\,\frac{USD}{kWh} )

C = 16544.35\, USD

3 0
3 years ago
A block whose weight is 45 N rests on a horizontal table. A horizontal force of 36 N is applied to the block. The coefficient of
riadik2000 [5.3K]

Answer:

1.5 m/s²

Explanation:

For the block to move, it must first overcome the static friction.

Fs = N μs

Fs = (45 N) (0.42)

Fs = 18.9 N

This is less than the 36 N applied, so the block will move.  Since the block is moving, kinetic friction takes over.  To find the block's acceleration, use Newton's second law:

∑F = ma

F − N μk = ma

36 N − (45 N) (0.65) = (45 N / 9.8 m/s²) a

6.75 N = 4.59 kg a

a = 1.47 m/s²

Rounded to two significant figures, the block's acceleration is 1.5 m/s².

Usually the coefficient of static friction is greater than the coefficient of kinetic friction.  You might want to double check the problem statement, just to be sure.

6 0
3 years ago
The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t
slamgirl [31]

Answer:

The charge is 2.75\times10^{-13}\ C

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length L=5.0\times5.0\times10^{-4}\ m

We need to calculate the linear charge density

Using formula of linear charge density

E=\dfrac{2k\lambda}{r}

\lambda=\dfrac{Er}{2k}

Put the value into the formula

\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}

\lambda=1.1\times10^{-10}\ C/m

We need to calculate the charge

Using formula of charge

Q=\lambda\timesL

Put the value into the formula

Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})

Q=2.75\times10^{-13}\ C

Hence, The charge is 2.75\times10^{-13}\ C

5 0
2 years ago
Someone places a chocolate bar near a working radar set that is used to locate ships and airplanes. which best describes what is
hjlf
The chocolate softens and melts as it absorbs the microwaves, and it makes a mess.
7 0
3 years ago
Read 2 more answers
1. A sample of gas has a constant temperature and number of particles. As the volume of the gas sample is increased, the pressur
AURORKA [14]

Answer:

1.C

2.C

3.C

Explanation:

hope its help hehe:(

4 0
2 years ago
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