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3 years ago

Explain how it is possible for the smallest white dwarfs to be the most massive.

1 answer:

8 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.. The most massive stars, with eight times the mass of the sun or more, will never become white dwarfs<span>. Instead, at the end of their lives, they will explode in a violent supernova, leaving behind a neutron star or </span>black hole.

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A 20×10⁹charge is moved between two points A andB that are 30mm apart and have an electric potential difference of 600v between

Alona [7]

Answer:

John Felix Anthony Cena is an American professional wrestler, actor, and television presenter. He is currently signed to WWE. Born and raised in West Newbury, Massachusetts, Cena moved to California in 1998 to pursue a career as a bodybuilder.

Explanation:

7 0

3 years ago

A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s

Bogdan [553]

Answer:

a) $v=20.3m/s$

b) $a=2.35m/s^2$

Explanation:

From the exercise we know:

$x_{1}=30m$ ; $v_{1}=10m/s$ ; $t_{1}=3s$

$x_{2}=375m$ ; $v_{2}=50m/s$ ; $t_{2}=20s$

The formula for average velocity is:

$v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}$

a) $v=\frac{375m-30m}{20s-3s}=20.3m/s$

The formula for average acceleration is:

$a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}$

b) $a=\frac{(50-10)m/s}{(20-3)s}=2.35m/s^2$

4 0

3 years ago

What is the purpose of control group ?

kirill [66]

Control group in a scientific experiment is a group separated from the rest of the experiment, it is where the independent variable being tested cannot influence the results. It isolates the independent variable's effects on the experiment and can helps rule out alternative explanations of the experimental results.

6 0

3 years ago

An installation consists of a 30-kVA, 3-phase transformer, a 480-volt primary, and a 240-volt secondary. Calculate the largest s

Nikitich [7]

Answer: 45 A

Explanation:

Primary only protection 3-phase

I = 3 phase kVA / ( 1.723 * V)

I = 30000 / ( 1.732 * 480 ) = 36.085 A

Table 450.3(B)

Currents of 9A or more column

primary only protection = 125%

Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A

Table 450.3(B) Note 1 does not apply, use next smaller Table 240.6(A)

Next smaller = 45 A

5 0

1 year ago

(a) What is the escape speed on a spherical asteroid whose radius is 500. km and whose gravitational acceleration at the surface

navik [9.2K]

Answer:

a) v= 1732.05m/s

b) d=250000m

c) v= 1414.214m/s

Explanation:

Notation

M= mass of the asteroid

m= mass of the particle moving upward

R= radius

v= escape speed

G= Universal constant

h= distance above the the surface

Part a

For this part we can use the principle of conservation of energy. for the begin the initial potential energy for the asteroid would be $U_i =-\frac{GMm}{R}$ .

The initial kinetic energy would be $\frac{1}{2}mv^2$ . The assumption here is that the particle escapes only if is infinetely far from the asteroid. And other assumption required is that the final potential and kinetic energy are both zero. Applying these we have: