Answer:
Squats involve flexion (forward motion) and extension (backward on the way up), so would fit into the sagittal plane. Frontal plane motion would include leaning from left to right as in sidebends and lateral raises, or perhaps you might picture jumping jacks for a good image of movement along the frontal plane.
Answer:
The answer is a prism
Hope it helps...............
Answer:
average speed = 1.73m/s
average velocity = 3.33m/s
Explanation:
<em>we'll</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>average</em><em> </em><em>speed</em><em> </em><em>first</em>
<em>average</em><em> </em><em>speed</em><em> </em><em>=</em><em> </em><em>total</em><em> </em><em>distance</em><em> </em><em>/</em><em> </em><em>total</em><em> </em><em>time</em><em> </em>
<em>his</em><em> </em><em>total</em><em> </em><em>distance</em><em> </em><em>is</em><em> </em>300m + 100m
= 400m
and total time should be taken in seconds as you know
((2×60)+50) + 60s
= 230s
so let's divide,
400m/230s
1.73 m/s
next, mean velocity
that is,
mean velocity = final- initial displacement/time
we have to note <em>displacement</em><em> </em>( this is the distance between the initial point to final point) here
the displacement is 300-100
so, 200m
we already calculated total time
but that cant be taken here
230 - 170
is the original time to travel 200m
that is, 60s
so we divide
200/60
3.33m/s
Since acceleration is constant
So the distance moved in constant acceleration will be given as

as we know that


t = 17 s
so distance moved is given by


so distance moved will be 170 m