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Iteru [2.4K]
3 years ago
6

Which expressions are equivalent to 4(3] + (-4)) - 9?​

Mathematics
2 answers:
Tanya [424]3 years ago
8 0

Answer:

-1

Step-by-step explanation:

12-4-9=12-13=-1

Bogdan [553]3 years ago
6 0
I think it’s -12, i’m not sure though
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A line includes the points (4, 8) and (3, 5). What is its equation in slope-intercept form? Write your answer using integers, pr
stich3 [128]

Answer:

A line includes the points (4, 8) and (3, 5) whose equation in slope-intercept form will be :

y=3x-4

Step-by-step explanation:

The point slope form: (x_1,y_1) and(x_2,y_2)

(y-y_1)=m(x-x_1)

where : m = Slope of the line

m=\frac{y_2-y_1}{x_2-x_1}

A line includes the points (4, 8) and (3, 5).The equation of the line will be:

m=\frac{5-8}{3-4}=3

(y-8)=3\times (x-4)

y-8=3x-12

y=3x-4

(y=mx+c), where c is intercept at y axis.

The above equation represents slope-intercept form of the line.

6 0
3 years ago
Find me this result !!!!! bana bu sonucu bulun​
DIA [1.3K]

Answer:

Not sure about want u want but if you want the purple line it is y=4 . and the blue line is 24.1

5 0
3 years ago
A school bus during morning pickups to calculate its average speed between 2.8 km and 4.2 km.
kifflom [539]

<u>Answer: </u>

Option (c)

The average speed between 2.8 km and 4.2 km is 42 km/h

<u>Explanation:</u>

Given, the distance between 2.8 km and 4.2 km is 4.2 - 2.8 = 1.4 km

Time (in hours) between 2.8 km and 4.2 km

    = 0.084 – 0.051

     = 0.033 hr

Speed =\frac{Distance}{Time}

Speed = \frac{1.4}{0.033}

Speed = 42.4 km/hr = 42 km/h (rounded to nearest)

Therefore, the average speed between 2.8 km and 4.2 km is 42 km/hr

Hence, Option (C) is correct

4 0
3 years ago
18 in<br> find the area of the circle helppp pleaseeee
scZoUnD [109]
<h2><u><em>Answer: 1017.8760</em></u></h2><h2><u><em>Step-by-step explanation:</em></u></h2><h2><u><em>area A=πr2 </em></u></h2><h2><u><em>A=π×182 </em></u></h2><h2><u><em>A=324π </em></u></h2><h2><u><em>A=1017.87602 </em></u></h2><h2><u><em></em></u></h2><h2><u><em>also, circumferenceC=2πr</em></u></h2><h2><u><em>and, diameterd=2r</em></u></h2>

<u><em></em></u>

3 0
3 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

Sum of squares of differences = 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

Population mean, μ = $30,000

Sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

Now,

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

Since,                  

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0
4 years ago
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