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Alja [10]
3 years ago
12

(08.01)Consider the following pair of equations:

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

from the first equation

-x-y=-5

-x=y-5

: x=5-y. eqn 3

y= x+1

subtitute x in this equation

:- y= 5-y+1

y+y= 6

2y = 6

y=3

subtitute y in eqn 3

x=y-5

:- x=3-5

x= -2

Nat2105 [25]3 years ago
6 0

Answer:

(2,3)

Step-by-step explanation:

this is the only coordinate that can be plugged in and still be true. therefore, this is the only value that intersect and creates a point.

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Snowcat [4.5K]

Answer:

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Step-by-step explanation:

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4 years ago
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Example of a number bond for 12 ÷ 6 = 2
Natalka [10]

Answer:

like 2*6=12

Step-by-step explanation:

2 times 6 equals 12

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Jim and Mary are competing in a math contest. They have to calculate how much it takes to completely fill a canister with a radi
Greeley [361]

Answer:

V = pi times r-squared times h.

pi = 3.14

Step-by-step explanation:

or simply it means V= 251.327

6 0
2 years ago
A rock falls off a balcony. It’s height(in feet)is given by the formula f(x)= -16t^2+12.5t+150, where t is measured in seconds.
ELEN [110]

Answer: 3.47\ seconds

Step-by-step explanation:

Given the following function:

f(x)= -16t^2+12.5t+150

You need to follow these steps in order to solve the exercise:

1. Substitute f(x)=0:

0= -16t^2+12.5t+150

2. Now you need to apply the Quadratic formula. This is:

x=t=\frac{-b\±\sqrt{b^2-4ac} }{2a}

In this case, you can identify that:

a=-16\\b=12.5\\c=150

Then, you can substitute these values into the formula:

t=\frac{-12.5\±\sqrt{(12.5)^2-4(-16)(150)}}{2(-16)}

3. Evaluating, you get:

t_1=3.47\\\\t_2=-2.69

4. You must choose the positive value. Then:

t=3.47\ seconds

7 0
4 years ago
please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44
xeze [42]

Answer:

d = 55.5  

x = 1

c = 11

m = \frac{1}{122}

k = \frac{a}{(c + 5)}

Step-by-step explanation:

Sorry, the formatting is slightly hard to understand, but I think this is what you meant.

Q1.

\frac{1}{6}d - 8 = \frac{5}{8} x 2

Step 1. Simplify.

\frac{5}{8} x 2 = \frac{5}{8} x \frac{2}{1} = \frac{10}{8}

Step 2. Cancel out the negative 8.

\frac{1}{6}d - 8 = \frac{10}{8}

+ 8 to both sides (do the opposite: \frac{1}{6}d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)

\frac{1}{6}d = \frac{10}{8} + 8

Step 3. Simplify.

\frac{10}{8} + 8 = \frac{10}{8} + \frac{8}{1} = \frac{10}{8} + \frac{64}{8} = \frac{74}{8} = \frac{37}{4}

Step 4. Cancel out the \frac{1}{6}.

\frac{1}{6}d = \frac{37}{4}

÷ \frac{1}{6} from both sides (do the opposite: d is multiplied by \frac{1}{6} right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)

÷ \frac{1}{6} = x 6

So....

x 6 to both sides

d = \frac{37}{4} x  6 = \frac{37}{4} x \frac{6}{1} = \frac{222}{4} = \frac{111}{2} = 55.5

Step 5. Write down your answer.

d = 55.5

Q2.

3x - 4 + 5x = 10 - 2x × 3

Step 1. Simplify

3x - 4 + 5x = 3x + 5x - 4 = 8x - 4

10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x

Step 2. Cancel out the negative 6x

8x - 4 = 10 - 6x

+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)

14x - 4 = 10

Step 3. Cancel out the negative 4

14x - 4 = 10

+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)

14x = 14

Step 4. Divide by 14

14x = 14

÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])

x = 1

Step 5. Write down your answer.

x = 1

Q3.

7(c - 3) = 14 × 4

Step 1. Expand the brackets

7(c - 3) = (7 x c) - (7 x 3) = 7c - 21

Step 2. Simplify

14 x 4 = 56

Step 3. Cancel out the negative 21

7c - 21 = 56

+ 21

7c = 56 + 21

7c = 77

Step 4. Cancel out the ×7

7c = 77

÷ 7

c = 77 ÷ 7

c = 11

Step 5. Write down your answer.

c = 11

Q4.

11(\frac{m}{22} + \frac{3}{44}) = 87m + m × 5

Step 1. Expand the brackets

11(\frac{m}{22} + \frac{3}{44}) = (11 x \frac{m}{22}) + (11 x \frac{3}{44}) = (\frac{11}{1} x \frac{m}{22}) + (\frac{11}{1} x \frac{3}{44}) = \frac{11m}{22} + \frac{33}{44} = \frac{m}{2} + \frac{3}{4}

Step 2. Simplify.

87m + m x 5 = 87m + 5m = 92m

Step 3. Cancel out the add \frac{3}{4}

\frac{m}{2} + \frac{3}{4} = 92m

- \frac{3}{4}

\frac{m}{2} = 92m - \frac{3}{4}

\frac{m}{2} = \frac{92m}{1} - \frac{3}{4}

\frac{m}{2} = \frac{368m}{4} - \frac{3}{4}

\frac{m}{2} = \frac{368m - 3}{4}

Step 4. Cancel out the ÷ 4

\frac{m}{2} = \frac{368m - 3}{4}

x 4

2m = 368m - 3

Step 5. Cancel out the 368m

2m = 368m - 3

- 368m

-366m = - 3

Step 6. Cancel out the × -366

-366m = -3

÷ -366

m = \frac{-3}{-366}

m = \frac{1}{122}

Step 7. Write down your answer.

m = \frac{1}{122}

Q5.

ck + 5k = a

Step 1. Factorise

ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)

Step 2. Cancel out the × (c + 5)

k(c + 5) = a

÷ (c + 5)

k = a ÷ (c + 5)

k = \frac{a}{(c + 5)}

5 0
3 years ago
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