4 + (−1 2/3)<br> four plus -1 and 2/3 =?

If function f is a cubic polynomial which statement most accurately describes the function over the interview (0,1)

inysia [295]

Answer:

Option (B)

Step-by-step explanation:

From the given table,

With the increase in the values of x (from x = -2 to x = 2), values of the function is decreasing from x =2 to x = 4.

Interval (0, 1) lies in the domain of the function in which the y-values of the function are,

At x = 0,

f(0) = -6

At x = 1,

f(1) = 0

Therefore, values of the given function are increasing in the interval of (0, 1).

Option (B) will be the correct option.

7 0

3 years ago

What is the greatest common factor (GCF) of 24 and 40?

o-na [289]

Question:

What is the greatest common factor (GCF) of 24 and 40?

Answer:

8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Lucas compared the prices of some books. He wrote down the prices of the books rounded to the nearest dollar as shown.6, 6, 7, 7

Anon25 [30]

Answer:

The third plot.

Step-by-step explanation:

Use the process of elimination:

The first 4 numbers are 6,6,7,7

The first plot shows 6,6,6,7,7,7 which is not the answer.

Next , the numbers are 9, 10, 10, 10, 10, 10, 10

THERE ARE 6 Tens, ONLY ANSWER CHOICE C HAS 6 TENS

THAT IS THE ANSWER!!!

<h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : ) </em></u></h3><h3><u><em>And always, </em></u></h3><h3><u><em>SIMPLIFY BANANAS : ) Hope this helps!!! </em></u></h3>

3 0

3 years ago

Math homework please help new subject dont know it. (trolls = report)

Natasha2012 [34]

Find area on triangle:
A=(1/2)bh
A=(1/2)(8 units)(6 units)
A=(1/2)(48 units^2)
A=24 units^2
Just do the same for the rest of this page following the equation for the area of a triangle A=(1/2)(base)(height)

Find the error:
A=(1/2)bh
100m^2=(1/2)b(20m)
100m^2=(10m)b
10m=b
He forgot to multiply bh by 1/2

Area of parallelogram:
A=bh
A=(3 units)(3 units)
A= 9 units^2
The red line is the height and the bottom of the parallelogram is the base, just count the squares. Imagine cutting the parallelogram at the red line and moving that triangle piece to the other side, it’ll make a rectangle, that’s why the equation is the same.

6 0

3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

3 years ago

4 + (−1 2/3) four plus -1 and 2/3 =?