Question

Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 Na2CO3 , and aqueous nickel(II) chloride, NiCl 2 NiCl2 . Include physical states. molecular equation:
Na 2 CO 3 ( aq ) + NiCl 2 ( aq ) ⟶ 2 NaCl ( aq ) + NiCO 3 ( s ) Na2CO3(aq)+NiCl2(aq)⟶2NaCl(aq)+NiCO3(s) Enter the balanced net ionic equation for this reaction. Include physical states. net ionic equation:

Answer 1

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium carbonate and nickel (II) chloride is given as:

$Na_2CO_3(aq.)+NiCl_2(aq.)\rightarrow 2NaCl(aq.)+NiCO_3(s)$

Ionic form of the above equation follows:

$2Na^{+}(aq.)+CO_3^{2-}(aq.)+Ni^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow NiCO_3(s)+2Na^+(aq.)+2Cl^-(aq.)$

As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ni^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow NiCO_3(s)$

Hence, the net ionic equation is written above.