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4 years ago

A What does the data tell us? Using the storm data and the computer model, check all statements that are true.

Chemistry

2 answers:

ioda4 years ago

3 0

I think the answer is a. and d.

hope this helps!!

dem82 [27]4 years ago

3 0

It's A, B, and D. This question was also in my homework.

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How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous sol

mojhsa [17]

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

$2Al + 3Cu{(NO_3)}_2 \rightarrow 2Al{(NO_3)}_3 +3 Cu$

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

$Al \rightarrow Al^{3+} + 3e^-$

And copper goes from +2 to 0

$Cu^{2+} + 2e^-\rightarrow Cu$

On balancing the number of electrons we get:

For 1 mole of Al $6e^-$ is required.

Therefore for 2 moles of Al,

Total $(2\times6)$ F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

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4 0

2 years ago

A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to

melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the Henderson-Hasselbach (H-H) equation:

pH = pKa + log $\frac{[CH_3COO^-]}{[CH_3COOH]}$

For acetic acid, pKa = 4.75.

We calculate the original number of moles for acetic acid and acetate, using the given concentrations and volume:

CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻

CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to calculate the new pH, by using the new concentrations:

pH = 4.75 + log $\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L}$ = 5.54

6 0

3 years ago

Determine the number of significant figures in 478 cm

Grace [21]

Answer:

There are 3 significant figures on this one.

3 0

3 years ago

Question 20 (1 point)

romanna [79]

Answer:

A. The ratio of the element in glucose is different than in ethanol

Explanation:

The compounds given are;

Glucose C₆H₁₂O₆

Ethanol C₂H₆O

The two compounds given are different from one another. But they have the same elemental composition.

Ethanol is made up of Carbon, hydrogen and Oxygen and so also, Glucose

Now,

The number of atoms in both compounds are different;

Number of atoms

C H O

Glucose 6 12 6

Ethanol 2 6 1

8 0

3 years ago

Fred mixes a solution using two types of solutions: 0.60 liters containing 10% alcohol and 0.40 liters containing 35% alcohol. W

insens350 [35]

The alcohol concentration of the mixed solution is 20%

Simplification :

Based on the given condition, formulate :

35% ×0.40 + 0.6 ×10% ÷{ 0.4+0.6}

Calculate the product : $\frac{0.14+0.06}{0.4 + 0.6}$

Calculate the sum or difference : $\frac{0.2}{1}$

Any fraction with denominator 1 is equal to numerator : 0.2

Multiply a number to both numerator, denominator : 0.2 × $\frac{100}{100}$

Calculate the product or quotient : $\frac{20}{100}$

A fraction with denominator equals to 100 to a percentage 20%.

How do you find the concentration of a mixed solution?

In general when your are mixing two different concentrations together first calculate number of moles for each solution (n=CV ,V-in liter) then add them together it will be total moles,then concentration of mixture will be = total moles / total volume(liter).

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5 0

2 years ago