The process of transporting rock material is called

In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure

kirill [66]

Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

$P_{total}= P_1+P_2+P_3+\dots +P_n$

Here ,

Partial pressure of Gas A = 400mm of Hg
Partial pressure of Gas B = 220 mm of Hg
Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

$P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }$

Substitute ,

$P_{total}=( 400 + 220 + 140 )mm\ of \ Hg$

Add ,

$P_{total}= 760\ mm\ of \ Hg$

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.

4 0

2 years ago

The gas left in a used aerosol can is at a pressure of 103 kPa at 25.0 °C. If the can heats up to 50.0 °C, what is the pressure

Anton [14]

The question mentions a change in temperature from 25 to 50 °C. With that, the aim of the question is to determine the change in volume based on that change in temperature. Therefore this question is based on Gay- Lussac's Gas Law which notes that an increase in temperature, causes an increase in pressure since the two are directly proportional (once volume remains constant). Thus Gay-Lussac's Equation can be used to solve for the answer.
Boyle's Equation: $\frac{P_{1} }{T_{1} }$ = $\frac{P_{2} }{T_{2} }$
Since the initial temperature (T₁) is 25 C, the final temperature is 50 C (T₂) and the initial pressure (P₁) is 103 kPa, then we can substitute these into the equation to find the final pressure (P₂).
$\frac{P_{1} }{T_{1} }$ = $\frac{P_{2} }{T_{2} }$ ∴ by substituting the known values, ⇒ (103 kPa) ÷ (25 °C) = (P₂) ÷ (50 °C)
⇒ P₂ = (4.12 kPa · °C) (50 °C)
= 206 kPa
Thus the pressure of the gas since the temperature was raised from 25 °C to 50 °C is 206 kPa

3 0

2 years ago

What is the wavelength (in nanometers) of light having a frequency of 3.9 x 1013 Hz?

Marta_Voda [28]

Yea I think the light is to fast

5 0

3 years ago

3. At a pressure of 405 kPa, the volume of a gas is 6.00 cm

monitta

The pressure gets increased to 486 kPa from 405 kPa, when the volume is decreased from 6 cm³ to 4 cm³.

Explanation:

In the present problem, the temperature is said to remain at constant and there is change in the pressure. So according to Boyle's law, the relationship between pressure and volume of any gaseous objects are inversely related to each other. In other words, the pressure attained by gas molecules in a container will be inversely proportional to the volume of the gas molecules occupied in the container, at constant temperature.

$V=\frac{1}{P}$

So, if two volumes V₁ and V₂ are considered, then their respective pressure will be represented as P₁ and P₂. Then, as per Boyle's law,

$V_{1}P_{1}=V_{2}P_{2}$

So let us consider, V₁ = 6 cm³ and V₂ = 4 cm³ and pressure P₁ = 405 kPa and we have to determine P₂.

Then, $6*405=5*P_{2}\\ \\P_{2}=\frac{2430}{5} =486 kPa$

So, the pressure at new volume of 4 cm³ is 486 kPa. It can be seen that as there is decrease in the volume, there is an increase in the pressure. So it satisfied the Boyle's law.

Thus, the pressure gets increased to 486 kPa from 405 kPa, when the volume is decreased from 6 cm³ to 4 cm³.

6 0

2 years ago

Molecules can be composed of ____. Select all that apply. … two of more of the same atoms two or more smaller molecules two or m

sertanlavr [38]

Answer:

Explanation:

A group of two or more smaller molecules is the correct answer

3 0

2 years ago