3/7h=33 ill give brainlyest if i can

Madison is preparing rice for 10 dinner guests. Each guest

Alexxx [7]

Answer:

door Sai so Lally shall icb kiddo do you have any questions

Step-by-step explanation:

ok CV bjf

7 0

3 years ago

You can work at most 20 hours next week. You need to earn at least $90 to cover your weekly expenses. Your dog walking job pays

Vadim26 [7]

Answer:

The answer in the procedure

Step-by-step explanation:

Let

x ----> the dog walking hours

y ----> the car washing hours

we know that

The system of linear inequalities is equal to

$x+y\leq20$ -----> inequality A

$9x+10y\geq 90$ -----> inequality B

Solve the system of inequalities by graphing

The solution is the shaded area

see the attached figure

Two possible combinations of hours are

(10,10) and (0,9)

Verify

For (10,10)

Substitute the value of x and the value of y in both inequalities

Inequality A

$10+10\leq20$

$20\leq20$ -----> is true

Inequality B

$9(10)+10(10)\geq 90$

$190\geq 90$ ----> is true

therefore

(10,10) is a possible solution

For (0.9)

Substitute the value of x and the value of y in both inequalities

Inequality A

$0+9\leq20$

$9\leq20$ -----> is true

Inequality B

$9(0)+10(9)\geq 90$

$90\geq 90$ ----> is true

therefore

(0,9) is a possible solution

5 0

3 years ago

In Exercise, find the derivative of the function. y = 3ex - xex

nevsk [136]

Answer:

the question is incomplete, the complete question is "find the derivative of the function $y=3e^{x}-xe^{x}$ "

answer: $\frac{dy}{dx}=(2-x)e^{x}$ .

Step-by-step explanation:

From the equation, $y=3e^{x}-xe^{x}$ , we approach the question using the differentiation of a product and differentiation of a sum simultaneously,

the differentiation of a sum is express as

f(x)=u(x)+v(x)+.....w(x) then

$\frac{df(x)}{dx}=\frac{du(x)}{dx}+\frac{dv(x)}{dx}+...\frac{dw(x)}{dx}.\\$

For the differentiation of a product we have

f(x)=u(x)v(x), then

$\frac{df(x)}{dx}=\frac{dv(x)}{dx}u(x)+\frac{du(x)}{dx}v(x)$

hence if we go by the formula we arrive at

for $y=3e^{x}$

let u(x)=3 hence du/dx=0 and

$v(x)=e^{x}$ and $\frac{dv(x)}{dx}=e^{x}$

hence $\frac{dy}{dx}=3e^{x}+0e^{x}\\\frac{dy}{dx}=3e^{x}---equation 1\\$

Also for $y=-xe^{x}\\\frac{dy}{dx}=-e^{x}-xe^{x}---equation 2$ .

if we add equation 1 and equation 2 we arrive at

$\frac{dy}{dx}=3e^{x}-e^{x}-xe^{x}\\\frac{dy}{dx}=(3-1-x)e^{x}\\\frac{dy}{dx}=(2-x)e^{x}$ .

4 0

3 years ago

Find the formula, in standard form y=ax^2+bx+c for a quadratic that has roots at x = 7 and x = -5, and has leading coefficient o

algol [13]

Answer:

Step-by-step explanation:

leading coefficient of 1 ==> a=1

sum of roots= 7+(-5)=2 ==> b= - 2

Product of roots=-35 ==> c=-35

Formula is y=x²-2x-35=(x-7)(x+5)

5 0

3 years ago

Hello! I was wondering if anyone can help me out on this question?

Ira Lisetskai [31]

Answer:

Function 2

Step-by-step explanation:

Function 2 or line q would have a greater slope

Please mark as brainliest answer

7 0

3 years ago