Answer:
a. 
Step-by-step explanation:
The given equation is;

To solve by the x-intercept method we need to graph the corresponding function using a graphing calculator or software.
The corresponding function is

The solution to
is where the graph touches the x-axis.
We can see from the graph that; the x-intercepts are;
(-1,0),(3,0) and (6,0).
Therefore the real solutions are:

Solve the equation for
x
by finding
a
,
b
, and
c
of the quadratic then applying the quadratic formula.
Exact Form:
x
=
−
3
±
√
6
3
Decimal Form:
x
=
−
0.18350341
…
,
−
1.81649658
…
Answer:
The probability that Chang gets dressed with a white shirt and tan pants is 25%.
Step-by-step explanation:
Given that Chang has 2 shirts, a white one and a black one, and he also has 2 pairs of pants, one blue and one tan, to determine what is the probability, if Chang gets dressed in the dark, that he winds up wearing the white shirt and tan pants the following calculation must be performed:
Each shirt = 50% chance
Each pants = 50% chance
0.50 x 0.50 = X
0.25 = X
Therefore, the probability that Chang gets dressed with a white shirt and tan pants is 25%.
Answer:
13
Step-by-step explanation:
You have to divide 52 by 4 as there are 4 types of plants. It says that they were divided equally and that there is four of them so 52 divided by 4 is 13.
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.
to find the least common multiple, you need to first figure out what the prime factors have in common.

each have two twos. both have one 5, so we know our answer will look something like

now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.
one has one 3 and one has two, so we need two threes. now our equation is

what's the only number we have to deal with? 7...
how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes