I think 13 pounds for extras and all not sure just my thought :)
Answer:
A.. 2
C.. 5
E.. 10
Step-by-step explanation:
If x represents the number of cars that wash Aron, then the domain of x must contain only integers and positive numbers (natural numbers)
This, because Aron can not wash -3 cars, it would be absurd then for x to be a negative number.
In the same way Aron can not wash 1.29 cars. Or washed 1 car or washed 2, it is not consistent in this case to say that washed a car and a half, for example.
Therefore the correct answer is the options.
A.. 2
C.. 5
E.. 10
Answer:
1) 1 element
2) 13 elements
3) 22 elements
4) 40 elements
Step-by-step explanation:
1) Only one element will have no tails: the event that all the coins are heads.
2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.
3) There are
elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are
possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22
4) We can have:
- A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
- One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)
For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)
For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).
This gives us a total of 18+22 = 40 possibilities.
Answer:
2/3 is the constant of proportionality.