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atroni [7]
3 years ago
8

Which of the following is an example of gene splicing? A. a mutation that occurs during meiosis results in a chromosomal abnorma

lity B. a segment of human DNA is inserted into the DNA sequence of a bacterium C. two human chromosomes pair up during meiosis and exchange parts of their DNA D. a genetically identical copy of an entire organism is produced through cloning
Biology
1 answer:
krok68 [10]3 years ago
6 0
A. The mutation that occurs during meiosis is a sure way of gene splitting I presume:)
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Detached earlobes are dominant. The mother’s genotype is EE, and the father’s genotype is ee. What is the chance that he will ha
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100% all offspring will be Ee - showing the dominant trait - detached earlobes
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What are the classification levels of humans for order, suborder, family, tribe, genus, and species? Group of answer choices Mam
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Answer: Human classification levels for order, suborder, family, tribe, genus and species are;

Primates, Primates, Haplorhini, Hominidae, Hominini, Homo, and sapiens , Hominidae, Hominini, Homo, and sapiens

Explanation:

Human taxonomy is the systematic classification of humans.

The order is primates include placenta animals including humans, that have good eyesight, flexible hands and feet, well developed brain and they include man, lemurs, apes e.t.c.

Suborder Haplorhini have a plate which cause a separation between the temporal fossa and eye socket.

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Humans are called homo sapiens which means wise man. It is a Latin word...

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4 0
3 years ago
1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently
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Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

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Photosynthetic reactions are made up of two parts: the light dependent reactions and the carbon fixation reactions. In the light dependent reactions, chlorophyll and other photosynthetic pigments absorb light energy from the sun and conserve it as ATP and NADPH with a simultaneous release of oxygen. The carbon fixation reactions are driven by the products of the light dependent reactions.

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