Answer:
The answer to your question is below
Explanation:
1)
Balanced chemical reaction
2CH₃OH + 3O₂ ⇒ 2 CO₂ + 4H₂O
Reactant Element Product
2 C 2
8 H 8
8 O 8
Molar mass of CH₃OH = 2[12 + 16 + 4]
= 2[32]
= 64 g
Molar mass of O₂ = 3[16 x 2] = 96 g
Theoretical proportion CH₃OH/O₂ = 64 g/96g = 0.67
Experimental proportion CH₃OH/O₂ = 60/48 = 1.25
Conclusion
The limiting reactant is O₂ because the Experimental proportion was higher than the theoretical proportion
2)
Balanced chemical reaction
S₈ + 12O₂ ⇒ 8SO₃
Reactant Elements Products
8 S 8
24 O 24
Molar mass of S₈ = 32 x 8 = 256 g
Molar mass of O₂ = 12 x 32 = 384 g
Theoretical proportion S₈ / O₂ = 256 / 384
= 0.67
Experimental proportion S₈ / O₂ = 40 / 35
= 1.14
Conclusion
The limiting reactant is O₂ because the experimental proportion was lower than the theoretical proportion.
Answer : The number of moles of 
are 0.50 moles.
Solution : Given,
Volume solution = 0.25 L
Molarity of solution = 2.00 mole/L
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
Now put all the given values in this formula, we get number of moles.
By rearranging the term,
Number of moles of = 0.50 moles
Therefore, 0.50 moles of are there in the solution.
Answer:
A mol (approximately)represents the number 6.02 X 10^^23. Mols become useful when we learn that, for any element on the periodic table, 6.02 X 10^^23 atoms of that element have a mass equal to the atomic mass in grams. So, on the periodic table carbon has an atomic mass of 12.011. That means: 12.011 grams of carbon is made up of 6.02 X 10^^23 atoms.
The above question is tricky.
If the question considers 1 molecule of SO2 as a particle, then the answer is 1.80 * 6.02 X 10^^23
If the question considers the S as one particle, and the O2 as 2 more particles, then the answer is: 3 * 1.8 * 6.02 X 10^^23.
Explanation:
hope it helps U
Explanation:
A B C D isme koyi ans hain doond lo
