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almond37 [142]
4 years ago
14

The first quartile of a data set is 2.5. which statement about the data values is true?

Mathematics
1 answer:
Luden [163]4 years ago
5 0

Answer:

The correct option is D.

Step-by-step explanation:

In a data set we have three quartiles and the second quartile is known as median.

First quartile Q₁ divides the data set in 1:3. It means \frac{1}{4} of the data set are less than or equal to Q₁ and \frac{3}{4} of the data set are more than or equal to Q₁.

Second quartile Q₂ divides the data set in 1:1. It means \frac{1}{2} of the data values are less than or equal to Q₂ and \frac{1}{2} of the data values are more than or equal to Q₂.

Third quartile Q₃ divides the data set in 3:1. It means \frac{3}{4} of the data values are less than or equal to Q₃ and \frac{1}{4} of the data values are more than or equal to Q₃.

It is given that first quartile of a data set is 2.5. It means \frac{1}{4} of the data set are less than or equal to 2.5 and \frac{3}{4} of the data set are more than or equal to 2.5.

Therefore the correct option is D.

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18+32=50

<h3> the answer is 50</h3>
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If two lines intersect, then the intersection is exactly two points. True or false
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Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appea
makkiz [27]

Answer:

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}

P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}

P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}

P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}

P(\frac{A}{B})=\dfrac{3}{15}

P(\frac{A}{B})=\dfrac{1}{5}

P(\frac{A}{B})=0.2

Therefore, the required probability is 0.2.

3 0
3 years ago
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