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miv72 [106K]
4 years ago
12

Find the Perimeter of the polygon if angle B= angle D Please Help Trying to graduate.

Mathematics
1 answer:
Dvinal [7]4 years ago
6 0

Answer:

P = 60 cm

Step-by-step explanation:

To solve this question we will use the property of the tangents drawn from a point to a circle.

"Length of tangents drawn from a point to a circle are equal in measure."

By this property,

Therefore, BG ≅ FB ≅ 7.5 cm

AG ≅ AH ≅ 6.5 cm

CF ≅ EC ≅ 8.5 cm

Since m∠B ≅ m∠D

Therefore, length of tangents FB ≅ GB ≅ DE ≅ DH ≅ 7.5 cm

Since, Perimeter of ABCD = AB + BC + CD + DA

AB = 7.5 + 6.5 = 14 cm

BC = 7.5 + 8.5 = 16 cm

CD = 8.5 + 7.5 = 16 cm

DA = 7.5 + 6.5 = 14 cm

Now Perimeter = 16 + 16 + 14 + 14 = 60 cm

Therefore, P = 60 cm will be the answer.

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The effect of wearing different types of running shoes on the time it takes to complete a race is being studied in an experiment
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Answer:

Direct contr

Step-by-step explanation:

I took the test and the guy who said replication was wrong. He cost me a point

3 0
3 years ago
What is the area? I need the answer now​
Tpy6a [65]

Answer:

192

Step-by-step explanation:

treat them as two rectangles. So take the first and you see that its 8 by 12, so 8 times 12, which equals 96. then look at the other rectangle. Its the same so do the same thing 8 times 12 equals 96. then add the totals to find the area. 96+96=192

3 0
3 years ago
I need major assistance for number 12,13
navik [9.2K]
12: Right Angle.

There is a box where K and M is located

13: This one is very confusing. But I would say the answer is either acute or right.

The triangle makes the square acute. But there is a square located. 

Hope this helps.
7 0
3 years ago
The polygons are similar solve for x
Gnom [1K]

Answer:

x=12

Step-by-step explanation:

14/21=16/(x+12)

cross multiply

14(x+12)=16(21)

14x+168=336

14x=336-168

14x=168

x=12 (so the side would be x+12=24)

You could also see that 14 is 2/3 of 21, so 16 has to be 2/3 of x+12.  That means x+12 would have to equal 24.  If you take the 12 away from 24, x=12.

6 0
3 years ago
What are the endpoint coordinates for the mid segment of △PQR that is parallel to PQ?
diamong [38]

Answer:

So the end points of the mid segment are:

S(-3.5,0.5)

T(-1,-0.5)

Step-by-step explanation:

First of all we need to list the co-ordinates of the points of the triangle shown.

P\rightarrow(-3,3)

Q\rightarrow(2,1)

R\rightarrow(-4,-2)

We need to find mid segment of the triangle which is parallel to segment PQ. This would mean we need to find midpoints of segment PR and QR and then join the points to get mid segment.

Midpoint Formula:

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Midpoint of PR:

S((\frac{-3+(-4)}{2},\frac{3+(-2)}{2})\\\\(\frac{-3-4}{2},\frac{3-2}{2})\\\\(\frac{-7}{2},\frac{1}{2} )

S(-3.5,0.5)

Midpoint of QR:

T(\frac{2+(-4)}{2},\frac{1+(-2)}{2})\\\\(\frac{2-4}{2},\frac{1-2}{2} )\\\\(\frac{-2}{2},\frac{-1}{2}

T(-1,-0.5)

So the end points of the mid segment are:

S(-3.5,0.5)

T(-1,-0.5)

By mid segment theorem we know that the line joining midpoints of two sides of a triangle is parallel to the 3rd side.

∴ We know ST is parallel to PQ  

4 0
3 years ago
Read 2 more answers
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