Answer:
2403 m/s^2
Explanation:
The gravitational potential energy of the froghopper when it reaches the maximum height is equal to the kinetic energy at the moment of takeoff:
where
m = 12.7 mg is the mass of the froghopper
g = 9.8 m/s^2 is the acceleration due to gravity
h = 49.8 cm = 0.498 m is the maximum height reached
v = ? is the take-off velocity
Solving for v, we find
We now that the froghopper accelerates from
u = 0 m/s
to
v = 3.1 m/s
in a distance of
d = 2.00 mm = 0.002 m
So we can find the acceleration by using the following SUVAT equation:
Solving for a,
Answer:
distance and time
Explanation: the farther you go and how much time it will take you
When stopped, the velocity of the van is 0 m/s.
We can use the formula <em> = +</em> <em>at</em>, where <em>a </em>is acceleration.
0 m/s = 11.5 m/s + (3.5 s)<em>a</em>
<em>-</em>11.5 = 3.5a
<em>a ≈ </em>-3.28571429 m/s^2
Round it however you need.
<h2>Book will hit the foot with force 21.8 N</h2>
Explanation:
The momentum of any object = m v
here m is the mass of body and v is its velocity
Thus momentum P = 3.2 x 1 = 3.2 kg-m
As the book is falling freely , so it will fall with and acceleration g
The force exerted by it is = m g
Thus force = 2.18 x 10 = 21.8 N