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tiny-mole [99]
2 years ago
12

A current of 5. 0 amperes is passing through a piece of wire. Determine how long it takes for 30 coulombs of charge to pass thro

ugh this wire
Physics
1 answer:
Ainat [17]2 years ago
3 0

The time taken for the charge to pass through the cross-section of the wire is 6.0s.

Given the data in the question;

Current; I = 5.0A

Charge; Q = 30C

Time; t =  \ ?

<h3>Current</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = \frac{Q}{t}

Where Q is the charge and t is time elapsed.

We substitute our given values into the expression above to determine the time it took the charge to pass through this wire.

I = \frac{Q}{t}\\ \\5.0A = \frac{30C}{t} \\\\t = \frac{30C}{5.0A} \\\\t = 6.0s

Therefore, the time taken for the charge to pass through the cross-section of the wire is 6.0s.

Learn more about current: brainly.com/question/3192435

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A certain carbon monoxide molecule consists of a carbon atom mc = 12 u and an oxygen atom mo = 17 u that are separated by a dist
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Answer:

a)  x_{cm} = m₂/ (m₁ + m₂)   d , b)   x_{cm} = 52.97 pm

Explanation:

The expression for the center of mass is

                x_{cm} = 1 / M  ∑ x_{i} m_{i}

Where M is the total masses, mI and xi are the mass and position of each element of the system.

Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon

              x_{cm} = 1 / (m₁ + m₂)   (0+ m₂ x₂)

Let's reduce the magnitudes to the SI system

             m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg

             m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg

             d = 128 pm = 128 10⁻¹² m

The equation for the center of mass is

               x_{cm} = m₂/ (m₁ + m₂)   d

b) let's calculate the value

            x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷    128 10-12

            x_{cm} = 52.97 10⁻¹² m

            x_{cm} = 52.97 pm

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