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tiny-mole [99]
2 years ago
12

A current of 5. 0 amperes is passing through a piece of wire. Determine how long it takes for 30 coulombs of charge to pass thro

ugh this wire
Physics
1 answer:
Ainat [17]2 years ago
3 0

The time taken for the charge to pass through the cross-section of the wire is 6.0s.

Given the data in the question;

Current; I = 5.0A

Charge; Q = 30C

Time; t =  \ ?

<h3>Current</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = \frac{Q}{t}

Where Q is the charge and t is time elapsed.

We substitute our given values into the expression above to determine the time it took the charge to pass through this wire.

I = \frac{Q}{t}\\ \\5.0A = \frac{30C}{t} \\\\t = \frac{30C}{5.0A} \\\\t = 6.0s

Therefore, the time taken for the charge to pass through the cross-section of the wire is 6.0s.

Learn more about current: brainly.com/question/3192435

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It is now 9:11 a.m. but when the bell rings at 9:12 a.m. Susie will be late for Mrs. Garner's U.S. History class for the 3rd tim
GaryK [48]

Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

6 0
2 years ago
A 7.0kg skydiver is descending with a constant velocity
Vikentia [17]

Answer:

The air resistance on the skydiver is 68.6 N

Explanation:

When the skydiver is falling down, there are two forces acting on him:

- The force of gravity, of magnitude mg, in the downward direction (where m is the mass of the skydiver and g is the acceleration due to gravity)

- The air resistance, R, in the upward direction

So the net force on the skydiver is:

F=mg-R

where

m = 7.0 kg is the mass

g=9.8 m/s^2

According to Newton's second law of motion, the net force on a body is equal to the product between its mass and its acceleration (a):

F=ma

In this problem, however, the skydiver is moving with constant velocity, so his acceleration is zero:

a=0

Therefore the net force is zero:

F=0

And so, we have:

mg-R=0

And so we can find the magnitude of the air resistance, which is equal to the force of gravity:

R=mg=(7.0)(9.8)=68.6 N

6 0
3 years ago
The escape velocity of any object from Earth is 11.2 km/s. (a) Express this speed in m/s and km/h. (b) At what temperature would
natima [27]

Answer:

a ) 11.1 *10^3 m/s = 39.96 Km/h

b) T_{o2} =1.58*10^5 K

Explanation:

a)v_{es} =v_{rms}= 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h

b)

M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol

gas constant R = 8.31 j/mol.K

v_{rms} = \sqrt{ \frac{3RT}{M}}

So, v_{rms,o2} =\sqrt{ \frac{3RT_{o2}}{M_{o2}}}

multiply each side by M_{o2}, so we have

v_{rms,o2}^2 *M_{o2} =3RT_{o2}

solving for temperature T_{o2}

T_{o2} = \frac{v_{rms,o2}^2 *M_{o2}}{3R}

In the question given,v_{rms} =v_{es}

T_{o2} = \frac{(11.1*10^3)^2 *32.0*10^{-3}}{3*8.31}

T_{o2} =1.58*10^5 K

7 0
3 years ago
Miss Hu taught her class what makes night and day on Earth. She could not use the real Sun. She used a light bulb instead. In th
kherson [118]

B. model; it is the model of the sun

5 0
2 years ago
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Pls helppp :)List several examples of applied force, normal force, and friction that you’ve observed in your life.
Anon25 [30]

Answer:

an example for applied force is

Explanation:

The applied force is the force applied to the object to either displace it or change its shape.

5 0
2 years ago
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