B
a car engine burns gasoline; because chemical energy is converted
Answer:
Distance between two point charges, r = 0.336 meters
Explanation:
Given that,
Charge 1, ![q_1=-7.8\ \mu C=-7.8\times 10^{-6}\ C](https://tex.z-dn.net/?f=q_1%3D-7.8%5C%20%5Cmu%20C%3D-7.8%5Ctimes%2010%5E%7B-6%7D%5C%20C)
Charge 2, ![q_2=2.4\ \mu C=2.4\times 10^{-6}\ C](https://tex.z-dn.net/?f=q_2%3D2.4%5C%20%5Cmu%20C%3D2.4%5Ctimes%2010%5E%7B-6%7D%5C%20C)
Electric potential energy, U = -0.5 J
The electric potential energy at a point r is given by :
![U=k\dfrac{q_1q_2}{r}](https://tex.z-dn.net/?f=U%3Dk%5Cdfrac%7Bq_1q_2%7D%7Br%7D)
![r=k\dfrac{q_1q_2}{U}](https://tex.z-dn.net/?f=r%3Dk%5Cdfrac%7Bq_1q_2%7D%7BU%7D)
![r=9\times 10^9\times \dfrac{-7.8\times 10^{-6}\times 2.4\times 10^{-6}}{-0.5}](https://tex.z-dn.net/?f=r%3D9%5Ctimes%2010%5E9%5Ctimes%20%5Cdfrac%7B-7.8%5Ctimes%2010%5E%7B-6%7D%5Ctimes%202.4%5Ctimes%2010%5E%7B-6%7D%7D%7B-0.5%7D)
r = 0.336 meters
So, the distance between two point charges is 0.336 meters. Hence, this is the required solution.
Answer:
e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1
Explanation:
This is an ejercise in special relativity, where the speed of light is constant.
Let's carefully analyze the approach, we see the two events at the same time.
The closest event time is
c = (x₁-300) / t
t = (x₁-300) / c
The time for the other event is
t = (x₂- 600) / c
since they tell us that we see the events simultaneously, we can equalize
(x₁ -300) / c = (x₂ -600) / c
x₁ = x₂ - 300
We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1