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marta [7]
3 years ago
14

Suppose you throw a rock nearly straight up at a coconut on

Physics
1 answer:
Rama09 [41]3 years ago
4 0
The coconut cold dislodge on the way down due to gravity
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A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating along a string in the negative x-direction at
storchak [24]

Answer

given,

wavelength = λ = 18.7 cm

                    = 0.187 m

amplitude , A = 2.34 cm

v = 0.38 m/s

A)  angular frequency = ?

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

angular frequency ,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) the wave number ,

      K = \dfrac{2\pi}{\lambda}

     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

as the wave is propagating in -x direction, the sign is positive between x and t

y ( x ,t) = A sin(k  x - ω t)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75 t)

4 0
3 years ago
What transplant method would prevent the rejection of tissue after an organ transplant
denis-greek [22]
Using organs cloned from the cells of the patient <span>would prevent the rejection of tissue after an organ transplant.</span>
4 0
4 years ago
40 POINTS <br> Can someone please answer me questions 16 and 17
Tatiana [17]
16. Solids cannot transport heat through convection. Because solids are stuck in place so they can't flow and since they can't flow, there is no convection.
17. It is because the metal conducts heat faster that it feels colder than the wood, which conducted heat slower. In other words metals are good conductors of heat. It takes away your body heat as you touch it and which makes your body temperature to drop, therefore you feel the coldness when you touch a piece of metal.
6 0
3 years ago
8. How many calories of heat energy (Q) would be released as a 2,500 g iron (Fe) frying pan at 190˚C cools to 25˚C?
Sedaia [141]

Answer:

Q=197505J

Explanation:

From the question we are told that:

Mass m=2500g=2.5kg

Initial heat of pan i_h=190 \tetxtdegree

Final heat of pan f_h=25˚C \tetxtdegree

 

Generally the equation for Heat energy released is mathematically given by

 Q=mC \triangle T\\\\Q=2.5*462 *(190-26)\\\\Q=1155 *(190-26)\\\\Q=1155 *(171)\\

 Q=197505J

3 0
3 years ago
A 0.05-m3 rigid tank initially contains refrigerant-134a at 0.8 MPa and 100 percent quality. The tank is connected by a valve to
lesya692 [45]

Answer:

A= 203 KJ

B= 54 Kg

Explanation:

The initial specific volumes and internal energies are obtained from A-12 for a given pressure and state. The enthalpy of the refrigerant in the supply line is determined using the saturated liquid approximation for the given temperature with data from A-11. The mass that has entered the tank is:

Δm = m₂ – m₁

= V(1/α₂ – 1/α₁)

= 0.05 (1/0.0008935 – 1/ 0.025645)Kg

= 54Kg

The heat transfer is obtained from the energy balance:

ΔU= m_i_n h_i_n+  Q_n_e_t

m₂u₂ – m₁u₂ = m_i_nh_i_n + Q_n_e_t

Q_n_e_t= m₂u₂ – m₁u₁ – m_i_n

= V/α₂u₂ - V/α₁u₁ – m_i_n

=(0.05/0.0008935 . 116.72 – 0.05/0.025645 . 246.82 – 54.108.28) Kj

= 203 KJ

8 0
3 years ago
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