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monitta
3 years ago
9

" alt="x + 5 \geqslant 12 \\ " align="absmiddle" class="latex-formula">
plz help me with this one. thanks
Mathematics
1 answer:
N76 [4]3 years ago
6 0

Hello from MrBillDoesMath!

Answer:

x >= 7

Discussion:

x + 5 >= 12                  =>  add -5 to both sides

x + 5 -5 >= 12 - 5        => as 5-5 = 0 and 12 =5 = 7

x >= 7

Thank you,

MrB

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Help please thank you
LuckyWell [14K]

Answer:

hmm i think its

1/2(x + y)

Step-by-step explanation:

because well... this would be eaiser for me if it said "of the" because "of the" is mostly used for multiply, but since it just said "the..." i can only guess. I think this may be the answer tho?

7 0
2 years ago
Read 2 more answers
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
100-99+98-97+96-95+...+8-7+6-5+4-3+2-1
lina2011 [118]
100-99+98-97+96-95+...+8-7+6-5+4-3+2-1\\\\=(100-99)+(98-97)+(96-95)+...+(4-3)+(2-1)\\\\=\underbrace{1+1+1+...+1}_{50}=\fbox{50}

8 0
3 years ago
Read 2 more answers
C(x) = mx + 500
grin007 [14]

Total cost as the function of shirts is :

C(x) = mx + 500 .

It is given that , The total cost to produce 100 shirts is $800.

800 = 100m + 500

m = 3

So , cost is given by :

C(x) = 3x + 500 .

Now , putting x = 1000 .

We get :

C(x) = 3x + 500

C(x) = 3(1000) + 500

C(x) = $3500

Therefore , cost of producing 1000 shirts is $3500 .

Hence, this is the required solution .

6 0
2 years ago
_____ compare one quantity to 100.
Alexxx [7]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
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