In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
given that :
The solute in the solution by mass percent = 10 %
mass percent = ( mass of solute / mass of solution ) × 100%
mass of solute in the solution is = 10 g
The solvent present in solution by mass percent = 90 %
the mass of solvent in the solution is is 90 g
Thus, In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
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Answer:
The rate of the reaction would be halved.
Explanation:
The reaction is first order with respect to reactant A and second order with respect to reactant B. The rate equation is [A][B]^2
If the concentration of A is doubled and the concentration of B is halved, rate = 2 × (1/2)^2 = 2 × 1/4 = 1/2.
The rate would be halved.
The answer to your question is an inequality.
(NH4)2S + Pb(NO3)2 ( 2NH4NO3 + PbS i think
Answer:
6CO2 + 6H20 + ENERGY = C6H12O6 + 6O2
Explanation:
Carbon dioxide + water + energy from light produces glucose and oxygen
