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kotegsom [21]
3 years ago
12

An experiment requires that each student use an 8.5 cm length of magnesium ribbon. How many students can do the experiment if th

ere is a 570 cm length of magnesium ribbon available?
Chemistry
2 answers:
melisa1 [442]3 years ago
7 0
570/8.5=67.0 58... you only have to take the natural part, si the answer is 67 students
BlackZzzverrR [31]3 years ago
5 0

In the particular experiment, each student uses 8.5 cm of ribbon.

The total length of the Mg ribbon present is 570 cm

so to find how many students can use the ribbon

number of students = total length of the ribbon / length each student uses

number of students = 570 cm / 8.5 cm/student = 67. 1 students

since it should be a whole number it should be 67

therefore 67 students can use the ribbon

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Answer:

0.6 grams of hydrogen are needed to react with 2.75 g of nitrogen.

Explanation:

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Chemical equation:

N₂ + 3H₂ → 2NH₃

Given mass of nitrogen = 2.75 g

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 2.75 g / 28 g/mol

Number of moles = 0.098 mol

Now we will compare the moles of nitrogen with hydrogen from balance chemical equation:

                   N₂             :          H₂

                    1               :           3

                   0.098       :        3×0.098 = 0.3 mol

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 0.3 mol × 2 g/mol

Mass = 0.6 g

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What element has the same number valence electrons as strontium?​
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A 4.75 Liter container is at a pressure of 120 kPa. What will its pressure be at a volume of 1.85L?
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Answer:

The answer to your question is 308.1 kPa

Explanation:

Data

Volume 1 = V1 = 4.75 l

Pressure 1 = P1 = 120 kPa

Volume 2 = V2 = 1.85 l

Pressure 2 = ?

Process

To solve this problem use Boyle's law.

                 P1V1 = P2V2

- Solve for P2

                 P2 = P1V1 / V2

- Substitution

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3 years ago
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