Question

A 500 mL sample of 0.5 M NaOH at 20 C is mixed with an equal volume of 0.5 M HCl at the same temperature in a calorimeter. The temperature rises to 23.21 C. Calculate the heat of the reaction.( - 53.72 kJ/mol)

Answer 1

Answer: Heat of reaction ∆H = -13.43kJ

Explanation:

The number of moles of NaOH = the number of moles of HCL = N

N = concentration × volume= CV = 0.5M × 500mL/1000ml/L

N= 0.5 × 0.5= 0.25mol

Since the Molar enthalpy is given by Hm = -53.72kJ/mol

Heat of reaction ∆H = N×Hm

∆H= 0.25mol × -53.72kJ/mol = -13.43kJ

Heat of reaction ∆H = -13.43kJ