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ivanzaharov [21]
4 years ago
9

The kw for water at 0 °c is 0.12× 10–14 m2. calculate the ph of a neutral aqueous solution at 0 °c.

Chemistry
1 answer:
belka [17]4 years ago
8 0
Remember that in water, the concentration of hydronium ions, or H⁺, will equal the concentration of hydroxide ions. That is [H⁺] = [OH⁻].

Remember that Kw = [H⁺][OH⁻] for water and if [H⁺] and [OH⁻] are both equal, we can easily solve for them by taking the square root of Kw.

[H⁺] = sqrt(0.12*10^-14) = 3.46*10^-8
(2 sig figs. Keep some extra so there will not be a rounding error.)

and remember that pH = -log[H⁺] = -log(3.46*10^-8) = <span><span>7.46
</span>
</span>(The rules for sig figs are that if you take the log of a number with x significant figures, then the result should have x significant decimal places.)

The pH of water is <span>7.46</span>
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