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Paladinen [302]

3 years ago

14

Find the area : 15in 44in 18in 22ina 165in²b 495in²c 330in²d 594in²

1 answer:

AnnyKZ [126]3 years ago

4 0

Area of a trapezoid: 1/2(a + b)*h, where a and b are the lengths of the two bases of a trapezoid and h is the height.

Plug 22 and 44 for a and b, respectively. Plug 15 for h.

1/2(22 + 44)*15

1/2(66)*15

1/2(990) = 495

b) 495 in²

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PilotLPTM [1.2K]

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What is the solution?<br> -10 = 2a – 4

DENIUS [597]

Answer:

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Step-by-step explanation:

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3 years ago

A rectangle is (x+10)ft by (x+4)ft. If a square of length xft on a side is cut from the rectangle, represent the remaining area

Andrei [34K]

Answer: $A(x)=14x+40$

Step-by-step explanation:

Given : The dimension of a rectangle is (x+10)ft. by (x+4)ft.

Then, Area of rectangle will be :-

$A_1(x)=(x+10)\times(x+4)=x^2+(10+4)x+40\\\\\Rightarrow\ A_1(x)=x^2+14x+40$

If a square of length xft on a side is cut from the rectangle, then the area of the square :-

$A_2(x)=x^2$

Now, the remaining area in the form of a polynomial function A(x) will be :-

$A(x)=A_1(x)-A_2(x)\\\\=x^2+14x+40-x^2=14x+40$

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3 years ago

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