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Paladinen [302]
3 years ago
14

Find the area : 15in 44in 18in 22ina 165in²b 495in²c 330in²d 594in²

Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0

Area of a trapezoid: 1/2(a + b)*h, where a and b are the lengths of the two bases of a trapezoid and h is the height.

Plug 22 and 44 for a and b, respectively. Plug 15 for h.

1/2(22 + 44)*15

1/2(66)*15

1/2(990) = 495

b) 495 in²

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Charlotte’s weekly paycheck is based on the number of hours worked during the week and on the weekend. If she works 13 hours dur
Schach [20]
X: earn per  hour during the week
y: earn per hour during the weekend

13x + 14y = 250.90
15x + 8y = 204.70

Multiply the first equation by 4 and the second equation by 7

52x + 56y = 1003.6
105x + 56y = 1432.90

Subtract the first equation from the second:

 53x = 429.30

x = 429.30/ 53
x = 8.10

Solve any of the equation for y:

15x + 8y = 204.70

y = [204.70 - 15(8.10)]/8 = 10.40

y - x = 10.40 -8.10 = 2.30

Answer: she earns $2.30 per hour more during the weekend than during the week.


8 0
3 years ago
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George is twice as old as Edward, and Edward's age exceeds Robert's age by 4 years. If the sum of the three ages is at least 56
marshall27 [118]

Answer:Robert's minimum age is 11 years.

Step-by-step explanation:

Let x represent George's age.

Let y represent Edward's age.

Let z represent Robert's age.

George is twice as old as Edward. It means that

x = 2y

Edward's age exceeds Robert's age by 4 years. It means that

z = y - 4

If the sum of the three ages is at least 56 years, it means that

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Substituting x = 2y and z = y - 4 into equation 1, it becomes

2y + y + y - 4 ≥ 56

4y - 4 ≥ 56

4y ≥ 56 + 4

y ≥ 60/4

y ≥ 15

z = y - 4 = 15 - 4

z ≥ 11

8 0
3 years ago
Order from least to greatest<br> 45<br> 11, 45, 520, 54
pentagon [3]

Answer: 11, 45, 45, 54, 520

4 0
3 years ago
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Anybody can help me with this one?
Masteriza [31]
The point would be (9,1)
6 0
2 years ago
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How u solve 55-[(5*2×3)-5*2]
slava [35]

Answer:

35

Step-by-step explanation:

55-[(5x2x3)-5x2]

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55-20

35

6 0
3 years ago
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