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slamgirl [31]
3 years ago
9

PLEASE ANSWER CORRECTLY

Mathematics
2 answers:
professor190 [17]3 years ago
7 0

Answer:

Options A and B.

Step-by-step explanation:

An ellipse is represented by the equation \frac{(x+5)^{2}}{625}+\frac{(y-7)^{2}}{49}=1

We have to find the foci of the given ellipse.

Ellipse having equation \frac{(x-h)^{2}}{a^{2} }+ \frac{(y-k)^{2} }{b^{2} }=1

Then center of this ellipse is represented by (h, k) and foci as (c, 0) and (-c, 0).

And c is represented by c² = a² - b²

So we co relate this equation with our equation given in the question.

a = √625 = 25

b = √49 = 7

and c² = (25)² - (7)²

c² = 625 - 49 = 576

c = ±√576

c = ±24

Now we know center of the ellipse is at (-5, 7) so foci can be obtained by adding and subtracting x = 24 from the coordinates of the center.

Center 1 will be [(-5+24=19), 7] ≈ (19, 7)

Center 2 will be [(-5-24=-29), 7] ≈ (-29, 7)

Therefore, options A and B are correct.

kirill [66]3 years ago
3 0

Answer:

A and B

Step-by-step explanation:

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A building contains two elevators, one fast and one slow. The average waiting time for the slow elevator is 3 min. and the avera
cupoosta [38]

Answer: The expected waiting time is 1\dfrac{2}{3}\ min

Step-by-step explanation:

Since we have given that

Average waiting time for slow elevator = 3 min

Average waiting time for fast elevator = 1 min

probability that a person choose the fast elevator = \dfrac{2}{3}

Probability that a person choose the slow elevator = \dfrac{1}{3}

So, the expected waiting time would be

E[x]=\sum xp(x)=3\times \dfrac{1}{3}+1\times \dfrac{2}{3}\\\\=1+\dfrac{2}{3}\\\\=\dfrac{3+2}{3}\\\\=\dfrac{5}{3}\\\\=1\dfrac{2}{3}\ min

Hence, the expected waiting time is 1\dfrac{2}{3}\ min

8 0
3 years ago
-g+2(3+g)=-4(g+1) answer please?
RideAnS [48]

Answer:

3+g=- 134

Step-by-step explanation:

5 0
3 years ago
A right triangle is graphed on a coordinate plane. Find the length of the hypotenuse. Round your answer to the nearest tenth. ​
Hoochie [10]

Answer:

7.6

Step-by-step explanation:

From the graph, we know the lengths of two legs.

  a = 3

  b = 7

Knowing this, we can use the Pythagorean Theorem to solve for c, the hypotenuse. (remember,  a^2 + b^2 = c^2)

c = √a2 + √b2  

= √(7)2 + √(3)2

= √49 + √9

= √58

= 7.6

8 0
4 years ago
URGENT WILL GIVE YOU 100 POINTS PLEASE ANSWER CORRECTLY
wariber [46]

Answer:

1. x = 18.4

2. x = -1.25

3. x = \frac{5}{12}

4. x = 12.3

5. x = 6.4

6. z = 5.8

7. x = \frac{1}{12}

8. x = -\frac{1}{4}

9. x = \frac{1}{3}

10. x = -9

11. z = 18

12. x = 7

13. x = -9

14. x = -36

15. x = -7

16. x = 8

17. z = -1.5

18. x = -\frac{45}{7}

19. x = 16

20. x = -12

21. x = \frac{8}{3}

22. x = -1.6

23. x = 1.8

24. x = -8.2

Step-by-step explanation:

1. x - 3.5 = 14.9 (add 3.5 to each side)

x = 18.4

2. x + 2.25 = 1 (subtract 2.25 from each side)

x = -1.25

3. -\frac{1}{3} = x - \frac{3}{4} (add \frac{3}{4} to each side)

\frac{3}{4} - \frac{1}{3}  = x (multiply \frac{3}{4} by \frac{3}{3} and \frac{1}{3} by \frac{4}{4} to get a common denominator)

\frac{9}{12} - \frac{4}{12} = x

\frac{5}{12} = x

4. x - 2.8 = 9.5 (add 2.8 to each side)

x = 12.3

5. x - 8.5 = -2.1 (add 8.5 to each side)

x = 6.4

6. z - 9.4 = -3.6 (add 9.4 to each side)

z = 5.8

7. x + \frac{5}{6} = \frac{11}{12} (subtract \frac{5}{6} from each side)

x = \frac{11}{12} - \frac{5}{6} (multiply \frac{5}{6} by \frac{2}{2} to get a common denominator)

x = \frac{11}{12} - \frac{10}{12}

x = \frac{1}{12}

8. -\frac{5}{6} + x = -\frac{13}{12} (add \frac{5}{6} to each side)

x = \frac{5}{6} - \frac{13}{12} (multiply \frac{5}{6} by \frac{2}{2} to get a common denominator)

x = \frac{10}{12} - \frac{13}{12}

x = -\frac{3}{12} = -\frac{1}{4}

9. x - \frac{1}{9} = \frac{5}{18} (add \frac{1}{9} to each side)

x = \frac{1}{9} + \frac{5}{18} (multiply \frac{1}{9} by \frac{2}{2} to get a common denominator)

x = \frac{2}{18} + \frac{5}{18}

x = \frac{6}{18} = \frac{3}{9} = \frac{1}{3}

10. x + 6 = -3 (subtract 6 from each side)

x = -9

11. z - 7 = 11 (add 7 to each side)

z = 18

12. -1 = x - 8 (add 8 to each side)

7 = x

13. -4x = 36 (divide each side by -4)

x = -9

14. -\frac{x}{3} = 12 (multiply each side by -3)

x = -36

15. 63 = -9x (divide each side by -9)

-7 = x

16. 6.4 = 0.8x (divide each side by 0.8)

8 = x

17. -2.8z = 4.2 (divide each side by -2.8)

z = -1.5

18. -\frac{7}{9}x = 5 (divide each side by -\frac{7}{9})

x = \frac{5}{1} ÷ -\frac{7}{9}

x = \frac{5}{1} (times) -\frac{9}{7}

x = -\frac{45}{7}

19. \frac{1}{2}x = 8 (divide each side by \frac{1}{2})

x = 16

20. -\frac{3}{4}x = 9 (divide each side by -\frac{3}{4})

x = -12

21. -\frac{7}{8}x = -\frac{21}{64} (divide each side by -\frac{7}{8})

x = -\frac{7}{8} ÷ -\frac{21}{64}

x = -\frac{7}{8} (times) -\frac{64}{21}

x = \frac{448}{168} = \frac{56}{21} = \frac{8}{3}

22. 1.6x = -3.2 (divide each side by 1.6)

x = -1.6

23. -\frac{1}{2} = -\frac{5}{18}x (divide each side by -\frac{5}{18})

1.8 = x

24. -2.5x = 20.5 (divide each side by -2.5)

x = -8.2

3 0
3 years ago
Read 2 more answers
A number is selected randomly from the integer from 10to30 what is the probability of picking a multiple of 4or5​
arlik [135]

Answer:

\frac{3}{7}

Step-by-step explanation:

Start by finding how many integers there are from 10-30...

30-10+1=20+1=21

Note we have to add 1 since it is inclusive.

Now, let's find how many multiples of 4 or 5 there are from 10-30...

4*3=12

4*4=16

4*5=20

4*6=24

4*7=28

5*2=10

5*3=15

5*4=20

5*5=25

5*6=30

5+5-1=9

Note we have to subtract 1 since 20 is counted twice.

The probability would be...

\frac{Multiples\ of\ four\ and\ five\ from\ 10-30}{Amount\ of\ integers\ between\ 10-30}=\frac{9}{21}=\frac{3}{7}

6 0
3 years ago
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