Question

PLEASE ANSWER CORRECTLY

Answer 1

Answer:

Options A and B.

Step-by-step explanation:

An ellipse is represented by the equation $\frac{(x+5)^{2}}{625}+\frac{(y-7)^{2}}{49}=1$

We have to find the foci of the given ellipse.

Ellipse having equation $\frac{(x-h)^{2}}{a^{2} }+ \frac{(y-k)^{2} }{b^{2} }=1$

Then center of this ellipse is represented by (h, k) and foci as (c, 0) and (-c, 0).

And c is represented by c² = a² - b²

So we co relate this equation with our equation given in the question.

a = √625 = 25

b = √49 = 7

and c² = (25)² - (7)²

c² = 625 - 49 = 576

c = ±√576

c = ±24

Now we know center of the ellipse is at (-5, 7) so foci can be obtained by adding and subtracting x = 24 from the coordinates of the center.

Center 1 will be [(-5+24=19), 7] ≈ (19, 7)

Center 2 will be [(-5-24=-29), 7] ≈ (-29, 7)

Therefore, options A and B are correct.

Answer 2

Answer:

A and B

Step-by-step explanation: